V2 = 250 ml
Explanation:
Given:
P1 = 0.99 atm. V1 = 240 ml
P2 = 0.951 atm. V2 = ?
We can use Boyle's law to solve for V2
P1V1 = P2V2
V2 = (P1/P2)V1
= (0.99 atm/0.951 atm)(240 ml)
= 250. ml
.5336
using avogadro’s law
Answer: 1.01 x 10^20 microliters.
Explanation: volume is defined as a three-dimensional measure of space that comprises a length, a width and a height. In other words, we are asked to convert from one volumetric measure to another (cubic centimeters to microliters) —volume is measured in units of cubic centimeters in metric, cubic inches or cubic feet in English measurement.
If, 1 cm³ = 1000 uL (microliters) then,
1 uL - - - - - - - - - 0.001 cm³ = 1 x 10^-3 cm
x uL - - - - - - - - - 1.01×10^-23 cm³
Therefore,
x uL = 1.01 x 10^-23 cm³ / 0.001 cm³
x uL = 1.01 x 10^(-23 - - 3)
x uL = 1.01 x 10^( - 23 + 3)
x uL = 1.01 x 10^20
Which is to say that a single rhodium atom of volume 1.01 x 10^23 cm³ would occupy 1.01 x 10^20 microliters.
The formula is B2O3. The charges need to equal each other to obtain a neutral compound of no charge hence 2 B has a charge of +6 and 3 O has a charge of -6 to cancel out each other, resulting in a stable uncharged compound.
