The law of definite proportions would state that a hydrate always contain exactly the same proportion of salt and water by mass.
strictly speaking, the law of definite proportion states that a compound always
contains exactly the same proportion of elements by mass.
But the law is often applied to groupings of elements in compound.
Hydrates are salt that have a certain amount of water asa part of their structure.
The water is chemically combined with the compound in a definite ratio.
Answer:
32 ° F
Explanation:
Freezing temp for water is 32 degrees at 1 atm
Once the student has finished his experiment, additional steps he may take are to analyze the data gathered and draw a conclusion, then publish his findings to be seen by his peers (other students).
<h3 /><h3>What comes after the experiment?</h3>
- Once an experiment is concluded, one must go over the data gathered.
- By this, we mean to analyze the information obtained through the experiment.
- This allows the student to draw a conclusion backed by evidence.
- Once complete, it is wise to share and discuss the findings with peers.
Therefore, we can confirm that once the experiment is completed, the most common action that follows is to draw a conclusion based on the analysis of the data gathered during the experiment, then discuss the findings with peers.
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The atomic number represents the number of protons present in an atom.Therefore,the answer is B.
The energy of a photon : 7.645 x 10⁻³⁴ J
<h3>Further explanation
</h3>
Radiation energy is absorbed by photons
The energy in one photon can be formulated as

Where
h = Planck's constant (6,626.10⁻³⁴ Js)
f = Frequency of electromagnetic waves
f = c / λ
, Hz
c = speed of light
= 3.10⁸ m/s
λ = wavelength
,m
wavelength λ of 2.60 ✕ 10⁻⁸ m
The energy :
