Answer:
The answer to your question is:
x = 1
y = 1
z = 0
Step-by-step explanation:
-2x + 2y + 3z = 0 (1)
-2x - y + z = -3 (2)
2x + 3y + 3z = 5 (3)
Solve (1) and (2)
Multiply 2 by 2
-2x + 2y + 3z = 0
-4x -2y + 2z = -6
-6x + 5 z = -6 (4)
Solve (2) and (3)
Multiply 2 by 3
-6x - 3y + 3z = -9
2x + 3y + 3z = 5
-4x + 6z = -4 (5)
Solve (4) and (5)
Multiply (4) by 2 and (5) by -3
-12x + 10 z = -12
12x - 18z = 12
-6z = 0
z = 0
Then
-4x + 6(0) = -4
-4x = -4
x = -4/-4
x = 1
Finally
-2(1) - y + (0) = -3
-2 - y = -3
-y = -3 + 2
y = 1
Answer:
The option is: <em>all real values except x = 7 and the x for which f(x) = -3</em>
Step-by-step explanation:
As the domain of f(x) is the set of all real values except 7. So it can be written as follows:
Domain of f(x) = { x ∈ R | x ≠ 7}
As the domain of g(x) is the set of all real values except -3. So it can be written as follows:
Domain of g(x) = { x ∈ R | x ≠ -3}
It is a common rule that the domain of a composite function (gºf)(x) will be the set of those input x in the domain of f for which f(x) is in the domain of g.
So, the option is: <em>all real values except x = 7 and the x for which f(x) = -3</em>
Keywords: domain, composite function
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F(x)=2x-5
k(x)=f(x+3)=2(x+3)-5=2x+6-5=2x+1
k(x)=2x+1
Answer:
B. No

Step-by-step explanation:
-A right angle triangle has two complimentary acute angles and one right angle.
-
is usually one of the acute angles and is equivalent to 90º minus it's complimentary acute angle.
-Complimentary angles add up to 90º.
#For complimentary angles:

The two acute angles cannot have the same Cosine value.
Hence, she's not correct.
Answer:
a: given
b: definition of congruent
c: definition of bisect
Step-by-step explanation:
just took the assignment