4 years ago

HELP ME PLEASE!!!!

1 answer:

7 0

$\dfrac{5}{\sqrt{10}}=\dfrac{5\cdot\sqrt{10}}{\sqrt{10}\cdot\sqrt{10}}=\dfrac{5\sqrt{10}}{10}=\dfrac{5\sqrt{10}}{5\cdot2}=\dfrac{\sqrt{10}}{2}\\\\\\\text{Used:}\sqrt{a}\cdot\sqrt{a}=a$

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Keith_Richards [23]

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3 years ago

An infinite geometric series has 1 and 1/5 as its first two terms: 1, 1/5, 1/25, 1/125, . . . What is the sum, S, of the infinit

dezoksy [38]

Answer: $\dfrac{5}{4}$

Step-by-step explanation:

Given: The first term of Geometric series : a=1

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$r=\dfrac{ar}{a}=\dfrac{\frac{1}{5}}{1}=\dfrac{1}{5}$

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$S_{\infty}=\dfrac{a}{1-r}\\\\\Rightarrow\ S_{\infty}=\dfrac{1}{1-\frac{1}{5}}=\dfrac{1}{\frac{4}{5}}\\\\\Rightarrow\ S_{\infty}=\dfrac{5}{4}$

Hence, the sum of the given infinite series = $\dfrac{5}{4}$

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3 years ago

Is (-5,6) a solution for 4x + 3y = 9

ozzi

Answer:

No.

Step-by-step explanation:

Insert the x and y, (-5 is x and 6 is y) into the equation. It should look like 4(-5)+3(6)=9. 4(-5)=-20 and 3(6)=18. -20+18=2 not 9.

(hope this helps :P)

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The answer is 35 please rate me the brainlest answer

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