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4 years ago

If c < d and x > 1, which of the following must be true?

Mathematics

1 answer:

Reika [66]4 years ago

4 0

Answer:

logc(x) > logd(x)

Step-by-step explanation:

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Joaquin has created a small treasure map that is in the shape of a square. He decides to make a larger version of the map, and o

likoan [24]

A - side of small map
a+6 - side of larger map
(a+6)² - area of larger map

(a+6)² = 121
(a+6)² = 11² |√(...)
a+6 = 11 |-6
a+6-6 = 11-6
<span>a = 5

</span>Answer A. <span>5 inches by 5 inches</span>

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4 years ago

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2/6+5/6 as a whole number

Dvinal [7]

Answer: 2/6+5/6 + 1.167

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2 years ago

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Addy bought a new shirt and she had a 20% off coupon . The coupon took $8.25 off of the price of her shirt. What did she pay wit

zloy xaker [14]

Answer:

$33

Step-by-step explanation:

Given: Addy had 20% off coupon.

The coupon took $8.25 off of the shirt price.

Lets assume the original cost of shirt be "x".

We know Addy had 20% off coupon, which help to reduce the price of shirt by $8.25.

∴ We can form an equation to know the original price of shirt.

⇒ $\frac{20}{100} \times x= \$ 8.25$

⇒ $\frac{1}{5} \times x= \$ 8.25$

Multiplying both side by 5

⇒ $x= 8.25\times 5$

∴ $x= \$ 41.25$

Hence, The original cost price of shirt was $41.25.

Next, finding the price paid by Addy for her new shirt by reducing coupon discount from the cost of shirt.

Price paid by Addy for her new shirt= $\$ 41.25- \$ 8.25= \$ 33$

Hence, Addy paid $33 for her new shirt.

8 0

3 years ago

Find the point of intersection of each pair of lines using substitution

lyudmila [28]

Answer:

ok ok ok ok ok ok o kom ko ko ko ko ko komk ko ko ko k kokok ok ok ok ok ok ok ok ok o-k ok ok

Step-by-step explanation:

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3 years ago

How many equivalence relations are there on the set 1, 2, 3]?

Alex787 [66]

Answer:

We need to find how many number of equivalence relations are on the set {1,2,3}

A relation is an equivalence relation if it is reflexive, transitive and symmetric.

equivalence relation R on {1,2,3}

1.For reflexive, it must contain (1,1),(2,2),(3,3)

2.For transitive, it must satisfy: if (x,y)∈R then (y,x)∈R

3. For symmetric, it must satisfy: if (x,y)∈R,(y,z)∈R then (x,z)∈R

Since (1,1),(2,2),(3,3) must be there is R, (1,2),(2,1),(2,3),(3,2),(1,3),(3,1). By symmetry,

we just need to count the number of ways in which we can use the pairs (1,2),(2,3),(1,3) to construct equivalence relations.

This is because if (1,2) is in the relation then (2,1) must be there in the relation.

the relation will be an equivalence relation if we use none of these pairs (1,2),(2,3),(1,3) . There is only one such relation: {(1,1),(2,2),(3,3)}

we can have three possible equivalence relations:

{(1,1),(2,2),(3,3),(1,2),(2,1)}

{(1,1),(2,2),(3,3),(1,3),(3,1)}

{(1,1),(2,2),(3,3),(2,3),(3,2)}

6 0

4 years ago