Answer:
1) The dependent variable is the monthly charge and the independent variable is the $110 to open the membership.
2)The dependent variable is the monthly charge because it will change depending on how many months you plan to keep your membership.
3)This relationship is linear because it will go up by $30 every month.
4)You could create a graph off of this information because all you would need to do is graph the cost each month.
5)I would need the number of month that I would keep the membership going and the amount that i have already paid.
Answer:
Step-by-step explanation:
Answer: A.) 2 <= X <= 6
B.) 13 < = X < = 39
Step-by-step explanation:
Given that a factory can work its employees no more than 6 days a week, that is, less than or equal to 6 days a week
And also, no less than 2 days per week. That is, greater than or equal to 2 day a week.
Let X represent the number of days an employee can work per week.
According to the first statement,
X < = 6
According to the second statement,
X >= 2
An inequality to represent the range of days an employee can work will be
2 < = X <= 6
To represent the range in hours, first convert the number of days to hour. Given that an employee can work
1 day = 6.5 hours
2 days = 2 × 6.5 = 13 hours
5 days = 6 × 6.5 = 39 hours
Therefore, the range will be
13 < = X < = 39
For the answer to the question above, <span>if
a1 = 2,
then
a2 = 3a1 + 1
a3 = 3a2 + 1 = 3
Then, we can finally solve for terms of sequence.
(3a1 + 1) + 1 = 9a1 + 4 = 9(2) + 4 = 22
So the answer to your question is,
</span><span>22, 67, 202, 607
</span>
I hope my answer helped you. Have a nice day!
Answer:
2(4x + 1)(x + 1)
Step-by-step explanation:
Given
8x² + 10x + 2 ← factor out 2 from each term
= 2(4x² + 5x + 1)
To factor the quadratic
Consider the factors of the product of the coefficient of the x² term and the constant term which sum to give the coefficient of the x- term
product = 4 × 1 = 4 and sum = + 5
The factors are + 1 and + 4
Use these factors to split the x - term
4x² + x + 4x + 1 ( factor the first/second and third/fourth terms )
= x(4x + 1) + 1 (4x + 1) ← factor out (4x + 1)
= (4x + 1)(x + 1), thus
4x² + 5x + 1 = (4x + 1)(x + 1) and
8x² + 10x + 2 = 2(4x + 1)(x + 1) ← in factored form
