What is the solution to -4(8-3x) >_6x-8

Mathematics

1 answer:

rosijanka [135]3 years ago

5 0

Answer:

x ≥4

Step-by-step explanation:

-4(8-3x) ≥6x-8

Distribute

-32+12x ≥6x-8

Subtract 6x from each side

-32+12x-6x ≥6x-6x-8

-32+6x ≥-8

Add 32 from each side

-32+32 +6x ≥-8+32

6x ≥ 24

Divide each side by 6

6x/6 ≥24/6

x ≥4

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