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3 years ago

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Which of the following statements best describes the transverse axis of a

1 answer:

TEA [102]3 years ago

4 0

Answer:

The transverse axis of a hyperbola equals the difference between the distances from any point on the hyperbola to each focus. Which is expressed in answer "C" in your list of possible answers.

Step-by-step explanation:

In fact, the definition of hyperbola is that of all point on the plane whose difference between their distance to each focus is a constant.

That constant can be determined in particular when one considers the distance to the actual vertex of the hyperbola (which is on the transverse axis) and whose distance to one of the focii is equal to the transverse axis plus the distance from the vertex to the focus, and from which needs to be subtracted the distance from the vertex to the focus, resulting then in exactly the transverse axis.

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What is the y-intercept -x 3y=9?

dedylja [7]

(0, 3)

<span>-x + 3y=9
to figure out the y-intercept, you must put the equation into y-intercept form first: y = mx + b

</span><span>-x+3y=9
3y = x + 9
y = (x/3) + (9/3)
y = x/3 + 3
</span>

7 0

3 years ago

The grade appeal process at a university requires that a jury be structured by selecting six individuals randomly from a pool of

romanna [79]

Answer: a) $\dfrac{3}{874}$

b) $\dfrac{30}{3059}$

c) $\dfrac{3575}{12236}$

Step-by-step explanation:

Given : Number of students : 11

Number of faculty members : 13

Total persons : $11+13=24$

Total number of ways to structure a jury of six people from a group of 24 people :-

$^{24}C_{6}=\dfrac{24!}{6!(24-6)!}=134596$

a) Number of ways of selecting a jury of all students :-

$^{11}C_{6}=\dfrac{11!}{6!(11-6)!}=462$

Then , the probability of selecting a jury of all students :-

$\dfrac{462}{134596}=\dfrac{3}{874}$

b) Number of ways of selecting a jury of all faculty :-

$^{13}C_{6}=\dfrac{13!}{6!(13-6)!}=462$

Then , the probability of selecting a jury of all students :-

$\dfrac{1716}{134596}=\dfrac{30}{3059}$

c) Number of ways of selecting a jury of two students and four faculty :-

$^{11}C_{2}\times^{13}C_{4}=\dfrac{11!}{2!(11-2)!}\times\dfrac{13!}{4!(13-4)!}=39325$

Then , the probability of selecting a jury of all students :-

$\dfrac{39325}{134596}=\dfrac{3575}{12236}$

3 0

3 years ago

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Lera25 [3.4K]

Answer:

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3 years ago

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Len [333]

Answer:

d=5

Step-by-step explanation:

1. use the distance formula: d= $\sqrt{(x_{2} - x_{2} )^{2} +(y_{2} -y_{1} )^{2}$

2. plug in the points: d= $\sqrt{(0-4)^{2} +(-9+6)^{2}$

3. solve problem inside parentheses: d= $\sqrt{(-4)^{2} +(-3)^{2}$

4. square -4 and -3: d= $\sqrt{16+9$

5. add:d= $\sqrt{25$

6. find square root: d=5

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4 years ago

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slavikrds [6]

Answer:

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3 years ago