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Rina8888 [55]
3 years ago
13

Find the distance between the points (0,-9) and(4,-6)

Mathematics
1 answer:
Len [333]3 years ago
8 0

Answer:

d=5

Step-by-step explanation:

1. use the distance formula: d=\sqrt{(x_{2} - x_{2} )^{2} +(y_{2} -y_{1} )^{2}

2. plug in the points: d=\sqrt{(0-4)^{2} +(-9+6)^{2}

3. solve problem inside parentheses: d=\sqrt{(-4)^{2} +(-3)^{2}

4. square -4 and -3: d=\sqrt{16+9

5. add:d=\sqrt{25

6. find square root: d=5

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Step-by-step explanation:

First, note that a flexible statistical learning method refers to using models that take into account agree difference in the observed data set, and are thus adjustable. While the inflexible method usually involves a model that has no regard to the kind of data set.

a) The sample size n is extremely large, and the number of predictors p is small. (BETTER)

In this case since the sample size is extremely large a flexible model is a best fit.

b) The number of predictors p is extremely large, and the number of observations n is small. (WORSE)

In such case overfiting the data is more likely because of of the small observations.

c) The relationship between the predictors and response is highly non-linear. (BETTER)

The flexible method would be a better fit.

d) The variance of the error terms, i.e. σ2=Var(ϵ), is extremely high. (WORSE)

In such case, using a flexible model is a best fit for the error terms because it can be adjusted.

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2 years ago
What would be the answer to this problem <img src="https://tex.z-dn.net/?f=%5Cfrac%7B7x-3%7D%7B9%7D%20%5Cgeq%208-2x" id="TexForm
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Answer:

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Step-by-step explanation:

6 0
2 years ago
Mark wants to paint a mural. He has 1 1/8 gallons of yellow paint, 1 1/9 gallons of green paint, and 7/8 gallon of blue paint. M
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Here is the set up:

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Please help me with these questions , thank you​
Angelina_Jolie [31]

Answer:

1. 4x^{3} + 26x² + 4x - 48

2. 2x^{3} - 23x² + 60x - 32

3. x^{5} + 7x^{3} - 4x + 2x^{4} + 14x² - 8

4. 2x^{7} + x^{6} - 28x^{5} + 3x + 12

Step-by-step explanation:

To multiply polynomials, simply distribute whatever's outside the largest set of parenthesis, then combine like terms.

1) Distribute the parenthesis (x + 6):

x(4x² + 2x - 8)  +  6(4x² + 2x - 8)

4x^{3} + 2x² -8x  +  6(4x² + 2x -8)

4x^{3} + 2x² -8x + 24x² + 12x - 48

Combine like terms:

4x^{3} + 26x² + 4x - 48

2) Distribute the parenthesis (x - 8):

x(2x² - 7x + 4)  +  (-8)(2x² - 7x + 4)

2x^{3} - 7x² + 4x  +  (-8)(2x² - 7x + 4)

2x^{3} - 7x² + 4x  +  -16x² + 56x - 32

Combine like terms:

2x^{3} - 23x² + 60x - 32

3) Distribute the parenthesis (x + 2):

x(x^{4} + 7x² - 4)  +  2(x^{4} + 7x² - 4)

x^{5} + 7x^{3} - 4x  +  2(x^{4} + 7x² - 4)

x^{5} + 7x^{3} - 4x + 2x^{4} + 14x² - 8

No like terms to combine, so:

x^{5} + 7x^{3} - 4x + 2x^{4} + 14x² - 8

4) Distribute the parenthesis (x + 4):

x(2x^{6} - 7x^{5} + 3)  +  4(2x^{6} - 7x^{5} + 3)

2x^{7} - 7x^{6} + 3x  +  4(2x^{6} - 7x^{5} + 3)

2x^{7} - 7x^{6} + 3x + 8  x^{6} - 28x^{5} + 12

Combine like terms:

2x^{7} + x^{6} - 28x^{5} + 3x + 12

hope this helps!

8 0
2 years ago
Cherie is jogging around a circular track. She
skelet666 [1.2K]

Answer:

Measure of minor angle JOG is 95.5^{\circ}

Step-by-step explanation:

Consider a circular track of radius 120 yards. Assume that Cherie starts from point J and runs 200 yards up to point G.  

\therefore m JG = 200 yards, JO=120 yards.  

Now the measure of minor arc is same as measure of central angle. Therefore minor angle is the central angle \angle JOG = \theta.

To calculate the central angle, use the arc length formula as follows.  

Arc\:Length\left(s\right) = r\:\theta  

Where \theta is measured in radian.

Substituting the value,

200=120\:\theta  

Dividing both side by 120,

\dfrac{200}{120}=\theta  

Reducing the fraction into lowest form by dividing numerator and denominator by 40.

\therefore \dfrac{5}{3}=\theta  

Therefore value of central angle is \angle JOG = \theta=\left(\dfrac{5}{3}\right)^{c}, since angle is in radian

Now convert radian into degree by using following formula,

1^{c}=\left(\dfrac{180}{\pi}\right)^{\circ}

So multiplying \theta with \left(\dfrac{180}{\pi}\right)^{\circ} to convert it into degree.

\left(\dfrac{5}{3}\right)^{c}=\left(\dfrac{5}{3}\right) \times \left(\dfrac{180}{\pi}\right)^{\circ}

Simplifying,

\therefore \theta = 95.49^{circ}

So to nearest tenth, \angle JOG=95.5^{circ}

8 0
3 years ago
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