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crimeas [40]
3 years ago
8

What is -3x6 with explanation

Mathematics
2 answers:
oksano4ka [1.4K]3 years ago
7 0

Answer:

It is 3.

Step-by-step explanation:

Positive times negative equals -3.

Papessa [141]3 years ago
4 0

Answer:

-18

Step-by-step explanation:


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Please help i don't have much time and nobody is answering!
aleksandrvk [35]

Answer:

x = 45

A triangle has to equal 180 degrees.

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Please don't answer wrong.​
Tamiku [17]

Answer:

<h3><u>Part (a)</u></h3>

<u />

<u>Equation of a circle</u>

(x-a)^2+(y-b)^2=r^2

where:

  • (a, b) is the center
  • r is the radius

Given equation:  x^2+y^2=6.25

Comparing the given equation with the general equation of a circle, the given equation is a <u>circle</u> with:

  • center = (0, 0)
  • radius = \sqrt{6.25}=2.5

To draw the circle, place the point of a compass on the origin. Make the width of the compass 2.5 units, then draw a circle about the origin.

<h3><u>Part (b)</u></h3>

Given equation:  x+y=1.5

Rearrange the given equation to make y the subject:  y=-x+1.5

Find two points on the line:

x=-2 \implies -(-2)+1.5=3.5\implies (-2,3.5)

x=2 \implies -(2)+1.5\implies-0.5\implies (2,-0.5)

Plot the found points and draw a straight line through them.

The <u>points of intersection</u> of the circle and the straight line are the solutions to the equation.

To solve this algebraically, substitute  y=-x+1.5  into the equation of the circle to create a quadratic:

\implies x^2+(-x+1.5)^2=6.25

\implies x^2+x^2-3x+2.25=6.25

\implies 2x^2-3x-4=0

Now use the quadratic formula to solve for x:

x=\dfrac{-b \pm \sqrt{b^2-4ac} }{2a}\quad\textsf{when }\:ax^2+bx+c=0

\implies x=\dfrac{-(-3) \pm \sqrt{(-3)^2-4(2)(-4)}}{2(2)}

\implies x=\dfrac{3 \pm \sqrt{41}}{4}

To find the coordinates of the points of intersection, substitute the found values of x into y=-x+1.5

\implies y=-\left(\dfrac{3 + \sqrt{41}}{4}\right)+1.5=\dfrac{3-\sqrt{41}}{4}

\implies y=-\left(\dfrac{3 - \sqrt{41}}{4}\right)+1.5=\dfrac{3+\sqrt{41}}{4}

Therefore, the two points of intersection are:

\left(\dfrac{3 + \sqrt{41}}{4},\dfrac{3-\sqrt{41}}{4}\right) \textsf{ and }\left(\dfrac{3 - \sqrt{41}}{4},\dfrac{3+\sqrt{41}}{4}\right)

Or as decimals to 2 d.p.:

(2.35, -0.85) and (-0.85, 2.35)

6 0
2 years ago
Please help me 80 points for who answers :)
Lana71 [14]

Answer:

the sum of two negative integers is a negative integer. true

the sum of two positive integers is a positive integer. true

to find the sum of a positive and a negative integer take the absolute value of each integer and then subtract these values.

true

the additive inverse of any integer and its opposite is equal to 0. false

The sum of any integer and its opposite is equal to zero.

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a model of a railroad station has has a scale of 1 inch equals 3.5 ft the dimensions of the model railroad station are 34 inches
andrew11 [14]
I would say that it would be 119ft by 63ft
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How do you right -6x-42=-16y in standard form?
Vinil7 [7]
16y=6x+42
16/16y=6x/16+42/16
y= 3x/8 + 21/8 
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3 years ago
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