B - 4 >_ 0
b >_ 4
-3b + 5 > 8
-3b > 3
b> -1
Answer:
There would be 63 grams of protein in 9 ounces of tuna.
Step-by-step explanation:
Equivalent ratios compare two different quantities the have the same rate regardless of the amount. In this example, for every 3 ounces of tuna, there are 21 grams of protein. We can write this as a ratio of: 3/21. Like fractions, we can simplify ratios by dividing the numerator and denominator by the same greatest common factor. In this case, we would divide both the numerator and denominator by 3: (3÷3)/(21÷3) = 1/7. So, our new ratio is for every ounce of tuna, we have 7 grams of protein. Using equivalent ratios, we can set up our ratios to solve for the grams of protein in 9 ounces of tuna: 1/7 = 9/x. Since we have to multiply both the numerator and denominator by the same factor, in this case 9, then our x = 63 grams of protein.
Step-by-step explanation:
Let y1 and y2 be (e^x)/2, and (xe^x)/2 respectively.
The Wronskian of them functions be
W = (y1y2' - y1'y2)
y1 = (e^x)/2 = y1'
y2 = (xe^x)/2
y2' = (1/2)(x + 1)e^x
W = (1/4)(x + 1)e^(2x) - (1/4)xe^(2x)
= (1/4)(x + 1 - x)e^(2x)
W = (1/4)e^(2x)
Since the Wronskian ≠ 0, we conclude that functions are linearly independent, and hence, form a set of fundamental solutions.
Answer:
I attached pictures of the two graphs, I hope they help!
Step-by-step explanation:
