G^5 -g = g(g^4 -1)=g(g^2 -1)(g^2 +1) = g(g-1)(g+1)(g^2 +1)
24g^2 -6g^4 = 6g^2(4 -g^2) = 6g^2(2 -g)(2 +g)
Answer:
B. 
Step-by-step explanation:
We know that the constant is $75. You only pay this once.
Whereas $0.55 you pay per mile. Which means that you will multiply 0.55 by how many miles you drive.
This means that the equation will look like:
Hope this helps! :)
Answer:
A = -4
B = 5
C = -3
Step-by-step explanation:
Standard form of a quadratic equation is y = Ax² + Bx + C
In the quadratic y = -4x² + 5x - 3, we can use this standard form to find A, B, and C.
Since -4 is the coefficient to x², A is -4.
Since 5 is the coefficient to x, B is 5.
Lastly, since -3 is the last term, C is -3.
So, the answer is:
A = -4
B = 5
C = -3
Answer:
64
Step-by-step explanation:
Evaluate x^4 + 3 x^3 - 6 x^2 - 12 x - 8 where x = 3:
x^4 + 3 x^3 - 6 x^2 - 12 x - 8 = 3^4 + 3×3^3 - 6×3^2 - 12×3 - 8
3^3 = 3×3^2:
3^4 + 3×3×3^2 - 6×3^2 - 12×3 - 8
3^2 = 9:
3^4 + 3×3×9 - 6×3^2 - 12×3 - 8
3×9 = 27:
3^4 + 3×27 - 6×3^2 - 12×3 - 8
3^2 = 9:
3^4 + 3×27 - 69 - 12×3 - 8
3^4 = (3^2)^2:
(3^2)^2 + 3×27 - 6×9 - 12×3 - 8
3^2 = 9:
9^2 + 3×27 - 6×9 - 12×3 - 8
9^2 = 81:
81 + 3×27 - 6×9 - 12×3 - 8
3×27 = 81:
81 + 81 - 6×9 - 12×3 - 8
-6×9 = -54:
81 + 81 + -54 - 12×3 - 8
-12×3 = -36:
81 + 81 - 54 + -36 - 8
81 + 81 - 54 - 36 - 8 = (81 + 81) - (54 + 36 + 8):
(81 + 81) - (54 + 36 + 8)
| 8 | 1
+ | 8 | 1
1 | 6 | 2:
162 - (54 + 36 + 8)
| 1 |
| 5 | 4
| 3 | 6
+ | | 8
| 9 | 8:
162 - 98
| | 15 |
| 0 | 5 | 12
| 1 | 6 | 2
- | | 9 | 8
| 0 | 6 | 4:
Answer: 64
