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vladimir2022 [97]
3 years ago
12

What number is one hundred thousand more than 75,000?

Mathematics
1 answer:
Gwar [14]3 years ago
6 0
The answer is 175,000
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A cash register contains 5 $10 bills and 3 $5 bills. you randomly pick 4 bills.
kobusy [5.1K]

a. The probability of picking exactly two $10 bills is \frac{3}{7}

b. The probability of picking at most one $5 bill is \frac{1}{2}

<em><u>Explanation</u></em>

Number of $10 bills = 5

and number of $5 bills = 3

Total number of bills= 5+3 = 8. You need to randomly pick 4 bills, so the total possible outcome = ^8C^4

<u>a. </u>

For getting exactly two $10 bills, you need to pick two $10 bills and two $5 bills. That means we will pick two $10 bill from 5 bills and two $5 bills from 3 bills.

So, the probability =\frac{(^5C^2)*(^3C^2)}{^8C^4} =\frac{10*3}{70}=\frac{30}{70}=\frac{3}{7}

<u>b.</u>

For getting at most one $5 bill, you need to pick <u>either zero or one</u> $5 bill.

If you pick <em>zero</em>  $5 bill, that means there are  <em>four</em><em>  </em>$10 bills

and if you pick <em>one  </em>$5 bill, that means there are <em>three  </em>$10 bills.

So, the probability =\frac{(^3C^0*^5C^4)+(^3C^1*^5C^3)}{^8C^4}=\frac{(1*5)+(3*10)}{70}=\frac{5+30}{70}=\frac{35}{70}=\frac{1}{2}


3 0
4 years ago
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