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kakasveta [241]
3 years ago
15

A deep-sea exploring ship is pulling up a diver at a rate of 25 feet per minute the diver is 200 feet below sea level how deep w

as in diver 10 minutes ago?
Mathematics
2 answers:
mezya [45]3 years ago
8 0

Answer:

the diver was 450 ft below sea level

Step-by-step explanation:

25ft per min

25x10=250

250+200=450ft

blsea [12.9K]3 years ago
7 0

Answer:

450 feet below sea level

Step-by-step explanation:

25 feet per minute 10 minutes, so you multipy them 25x10=250, and then add that to the level he's at right now, 200+250=450.

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The perimeter of a square newspaper ad is 40 centimeters. How long is each side?
Katyanochek1 [597]
The answer is:  "10 cm" .
____________________________________
Method 1)
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2L + 2w = 40 ;  Since the formula for perimeter of a rectangle (Note: a square is a rectangle) is:

                         P = 2L + 2w ;  Note:  L = length; w = width; P = perimeter;
______________________________________________________
 Factor out a "2":
_________________
" 2L + 2w = 40" ;

2 (L+ w) = 40;

Divide each side of the question by "2" ;
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         [2 (L + w)] / 2  = 40 / 2 ;
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 to get:  (L + w) = 20 ;

Note:  this "rectangle is a square" ; so L= w".
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20 /2 = 10 ;

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Each side is:  10 cm .
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Method 2)
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We are given: The perimeter (sum of the lengths of all sides) of a square is "40 cm."  Since a square has 4 sides of equal length:
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6 0
3 years ago
A garden is shaped in the form of a regular heptagon (seven-sided), MNSRQPO. A circle with center T and radius 25m circumscribes
Alenkinab [10]

The relationship between the sides MN, MS, and MQ in the given regular heptagon is \dfrac{1}{MN} = \dfrac{1}{MS} + \dfrac{1}{MQ}

The area to be planted with flowers is approximately <u>923.558 m²</u>

The reason the above value is correct is as follows;

The known parameters of the garden are;

The radius of the circle that circumscribes the heptagon, r = 25 m

The area left for the children playground = ΔMSQ

Required;

The area of the garden planted with flowers

Solution:

The area of an heptagon, is;

A = \dfrac{7}{4} \cdot a^2 \cdot  cot \left (\dfrac{180 ^{\circ}}{7} \right )

The interior angle of an heptagon = 128.571°

The length of a side, S, is given as follows;

\dfrac{s}{sin(180 - 128.571)} = \dfrac{25}{sin \left(\dfrac{128.571}{2} \right)}

s = \dfrac{25}{sin \left(\dfrac{128.571}{2} \right)} \times sin(180 - 128.571) \approx 21.69

The \ apothem \ a = 25 \times sin \left ( \dfrac{128.571}{2} \right) \approx 22.52

The area of the heptagon MNSRQPO is therefore;

A = \dfrac{7}{4} \times 22.52^2 \times cot \left (\dfrac{180 ^{\circ}}{7} \right ) \approx 1,842.94

MS = \sqrt{(21.69^2 + 21.69^2 - 2 \times  21.69 \times21.69\times cos(128.571^{\circ})) \approx 43.08

By sine rule, we have

\dfrac{21.69}{sin(\angle NSM)} = \dfrac{43.08}{sin(128.571 ^{\circ})}

sin(\angle NSM) =\dfrac{21.69}{43.08} \times sin(128.571 ^{\circ})

\angle NSM = arcsin \left(\dfrac{21.69}{43.08} \times sin(128.571 ^{\circ}) \right) \approx 23.18^{\circ}

∠MSQ = 128.571 - 2*23.18 = 82.211

The area of triangle, MSQ, is given as follows;

Area \ of \Delta MSQ = \dfrac{1}{2}  \times  43.08^2 \times sin(82.211^{\circ}) \approx 919.382^{\circ}

The area of the of the garden plated with flowers, A_{req}, is given as follows;

A_{req} = Area of heptagon MNSRQPO - Area of triangle ΔMSQ

Therefore;

A_{req}= 1,842.94 - 919.382 ≈ 923.558

The area of the of the garden plated with flowers, A_{req} ≈ <u>923.558 m²</u>

Learn more about figures circumscribed by a circle here:

brainly.com/question/16478185

6 0
3 years ago
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MAVERICK [17]
F(X)=13 Just Plug 10 into the X in the equation

7 0
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Snowcat [4.5K]

Answer:

A

Step-by-step explanation:

The volume (V) of a pyramid is

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area of square base = 4² = 16 and h = 4, hence

V = \frac{1}{3} × 16 × 4 = \frac{64}{3} = 21 \frac{1}{3} ft³

7 0
3 years ago
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Step-by-step explanation:

Putting values of x and y

2 = 4 + 2

2 = 6

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4 0
3 years ago
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