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kakasveta [241]
3 years ago
15

A deep-sea exploring ship is pulling up a diver at a rate of 25 feet per minute the diver is 200 feet below sea level how deep w

as in diver 10 minutes ago?
Mathematics
2 answers:
mezya [45]3 years ago
8 0

Answer:

the diver was 450 ft below sea level

Step-by-step explanation:

25ft per min

25x10=250

250+200=450ft

blsea [12.9K]3 years ago
7 0

Answer:

450 feet below sea level

Step-by-step explanation:

25 feet per minute 10 minutes, so you multipy them 25x10=250, and then add that to the level he's at right now, 200+250=450.

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The actual length of Wall C is 4 m. To represent Wall C, Noah draws a segment 16 cm long. What scale is he using?
hjlf

Answer:

\frac{1m}{4cm}

Step-by-step explanation:

First write the problem out as a fraction.

\frac{4}{16}

Next see if there is a GCF

4:1,2,4

16:1,2,4,8,16

Finally divide the numerator and denomenator by the GCF

\frac{4}{16} /4=\frac{1}{4}

4 0
3 years ago
7-x what does it equal.
kupik [55]

Answer: =-x+7

Step-by-step explanation:

5 0
3 years ago
Celeste wants to have her hair cut and permed and also go to lunch. She knows she will need $77. The perm costs twice as much as
UkoKoshka [18]
2x+5=77.
-5. -5
2x. = 72
2. 2
x= 36

to check all you do is plug in 36 into x
so you get 2(36)+5 which equals 77.


2x is the permed
5 is for lunch
77 total money they have
3 0
3 years ago
Use benchmarks to determine the customary and metric units you would use to measure the height of you house. Explain your answer
RideAnS [48]
Yards and meters because they has a good measurement. A mile and kilometer is way to big. A kilometer is 1000 meters and a mile is 5280 feet to be exact.
6 0
3 years ago
Read 2 more answers
Determine mu subscript x overbarμx and sigma subscript x overbarσx from the given parameters of the population and the sample si
Alex

Answer:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

And replacing we got:

\mu_{\bar X}= 32

\sigma_{\bar X} = \frac{77}{\sqrt{23}} =10.06

Step-by-step explanation:

Previous concepts

The central limit theorem states that "if we have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population with replacement, then the distribution of the sample means will be approximately normally distributed. This will hold true regardless of whether the source population is normal or skewed, provided the sample size is sufficiently large".

Let X the random variable who represents the variable of interest, with the following properties:

\mu =32,\sigma =77

We select a sample of n=23 nails.

From the central limit theorem we can approximate that the distribution for the sample mean \bar X is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

And replacing we got:

\mu_{\bar X}= 77

\sigma_{\bar X} = \frac{77}{\sqrt{23}} =10.06

6 0
3 years ago
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