8. There are 10 balls in a bag numbered from 1 to 10. Three balls are selected at random without replacement.

Mathematics

1 answer:

PIT_PIT [208]3 years ago

5 0

Answer:

a. 720

b. 0.3

Step-by-step explanation:

Three balls are selected at random without replacement.

First ball can be selected in 10 ways

Second ball can be selected in 9 ways

Third ball can be selected in 8 ways

Thus, there are 10×9×8 =720 different ways of selecting three balls.

There are three cases that satisfy this condition

first ball picked is 5, the others are not
first ball is not 5, second is 5, third is not
first and second ball is not five, third ball is 5

Each probabilities are:

$\frac{1}{10} * \frac{9}{9} *\frac{8}{8} =\frac{1}{10}$
$\frac{9}{10} *\frac{1}{9} *\frac{8}{8} =\frac{1}{10}$
$\frac{9}{10} *\frac{8}{9} *\frac{1}{8} =\frac{1}{10}$

Thus, one of the balls selected is the number 5 is then $\frac{1}{10} + \frac{1}{10} + \frac{1}{10} = \frac{3}{10}$

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5 0

3 years ago

Read 2 more answers

If the parent function f(x) = (2x − 3)3 is transformed to g(x) = (-2x + 3)3, which type of transformation occurs?

zimovet [89]

Answer:

it reflect over y axis.

Step-by-step explanation

Given: If the parent function f(x) = (2x − 3)³ is transformed to g(x) = (-2x + 3)³.

To find: Which type of transformation occurs.

Solution: We have given that

parent function f(x) = (2x − 3)³ .