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Y_Kistochka [10]
2 years ago
11

Answer fast whoever get it right gets BRAINLIEST!!!

Mathematics
1 answer:
dlinn [17]2 years ago
5 0
Is it d=8/3????......
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, list the first five terms of each sequence, and identify them as arithmetic or geometric.
sveta [45]

Answer: -2, 2, 6, 10, 14

It is an Arithmetic sequence.

Step-by-step explanation:

Given Recursive formula : A(n + 1) = A(n) + 4 ,  for n ≥ 1 and A(1) = -2.

A(2)=A(1 + 1) = A(1) + 4=-2+4=2

A(3)=A(2 + 1) = A(2) + 4=2+4=6

A(4)=A(3 + 1) = A(3) + 4=6+4=10

A(5)=A(4 + 1) = A(4) + 4=10+4=14

Hence, the  five terms of given sequence= -2, 2, 6, 10, 14

Since, there is common difference of 4 in two consecutive terms.

Therefore, it is an Arithmetic sequence.

5 0
3 years ago
“baka”<br> ,killua zoldyc
adell [148]
What is the question??
4 0
3 years ago
Read 2 more answers
Sarah has $55.00 to spend
GenaCL600 [577]
The equation that models the relationship between the amount of money Sarah has left is 55- 0.65x= y
8 0
3 years ago
Find an explicit solution of the given initial-value problem. (1 + x4) dy + x(1 + 4y2) dx = 0, y(1) = 0
MissTica

Answer:

a solution is 1/2 *tan⁻¹ (2*y) = - tan⁻¹ (x²) + π/4

Step-by-step explanation:

for the equation

(1 + x⁴) dy + x*(1 + 4y²) dx = 0

(1 + x⁴) dy  = - x*(1 + 4y²) dx

[1/(1 + 4y²)] dy = [-x/(1 + x⁴)] dx

∫[1/(1 + 4y²)] dy = ∫[-x/(1 + x⁴)] dx

now to solve each integral

I₁= ∫[1/(1 + 4y²)] dy = 1/2 *tan⁻¹ (2*y) + C₁

I₂=  ∫[-x/(1 + x⁴)] dx

for u= x² → du=x*dx

I₂=  ∫[-x/(1 + x⁴)] dx = -∫[1/(1 + u² )] du = - tan⁻¹ (u) +C₂ =  - tan⁻¹ (x²) +C₂

then

1/2 *tan⁻¹ (2*y) = - tan⁻¹ (x²) +C

for y(x=1) = 0

1/2 *tan⁻¹ (2*0) = - tan⁻¹ (1²) +C

since tan⁻¹ (1²) for π/4+ π*N and tan⁻¹ (0) for  π*N , we will choose for simplicity N=0 . hen an explicit solution would be

1/2 * 0 = - π/4 + C

C= π/4

therefore

1/2 *tan⁻¹ (2*y) = - tan⁻¹ (x²) + π/4

5 0
3 years ago
What describes the solution of the inequality y &gt; -15
Alex787 [66]

Answer:

paper

Step-by-step explanation:

8 0
2 years ago
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