Answer:
The ball will go to maximum height of 56.25 meters.
Step-by-step explanation:
It is given that, a ball is thrown vertically upward from the ground. Initial velocity of the ball, v = 60 ft/sec
Initial height is 0 as the ball is thrown from ground. The equation of projectile is given by :
h = 0
..............(1)
We need to find the maximum height reached by the ball. For maximum height,
t = 1.875 seconds
Put the values of t in equation (1). So,
h(t) = 56.25 meters
So, the ball will go to maximum height of 56.25 meters. Hence, this is teh required solution.
Answer:
The length of each of the other two sides would be 3.1 cm
Step-by-step explanation:
<u><em>The options of the question are</em></u>
A. 3.1 cm
B. 3.2 cm
C. 4.2 cm
D. 6.1 cm
we know that
An isosceles triangle has two equal sides and two equal interior angles
Let
x -----> the length of each of the two equal sides in the isosceles triangle
The perimeter of one isosceles triangle is equal to
Remember that
To maximize the use of the wire, the perimeter of 6 earrings (3 pairs of earrings) must be equal to 50 cm
so
Solve for x
therefore
The length of each of the other two sides would be 3.1 cm
Answer:
(3, -2)
Step-by-step explanation:
The <em>midpoint</em> of two points is half-way between the x-values and the y-values.
The formula is
M = ((x₁ + x₂)/2, (y₁ + y₂)/2)
For the points (5,-5) and (1,1),
Half way between the x values is
(x₁ + x₂)/2 = (5 + 1) /2 = 6/2 = 3
Half way between the y values is
(y₁ + y₂)/2= (-5 + 1)/2 = -4/2 = -2
M = (3, -2)
The graph below shows your two points at (5,-5) and (1,1) and the mid-point at (3, -2).
Answer:
X=0
Step-by-step explanation:
