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Vladimir [108]
3 years ago
7

PLEASE HELP!! The same numbers of each coin have a total of $6.00. There are nickles, dimes and quarters. How many of each coin

are there? Pls solve algebraically.i will give the brainliest answer!
Mathematics
2 answers:
Free_Kalibri [48]3 years ago
7 0

Answer:

Since there are the same amount we add all the values up.

Nickle = 0.05

Dime = 0.10

Quarter = 0.25

Add them all up

0.05 + 0.10 + 0.25 = 0.4

6 / 0.40 = 15

There is 15 of each coin

An equation would be 6 / (N + D + Q) = Answer

Hope this helps

Step-by-step explanation:

Harman [31]3 years ago
7 0

Answer: 15 of each coin

Step-by-step explanation:

So there are 3 types of coins and we know that there has to be the same number of coins. A nickle is worth 5, dime is 10, quarter is 25. So lets make an equation with the variable a. "A" equals the constant that each coin is multiplied by.

.5a + .10a + .25a = 6.00, lets solve for "a" now.

.40a = 6.00, then 6.00/.40 = 15

And there you go, there is 15 of each coin. Lets check if this is actually correct tho.

.5 x 15 = .75

.10 x 15 = 1.50

.25 x 15 = 3.75

.75 + 1.50 + 3.75 = 6.00

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An appliance manufacturer claims to have developed a compact microwave oven that consumes a mean of no more than 250 W. From pre
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Answer:

We conclude that a compact microwave oven consumes a mean of more than 250 W.

Step-by-step explanation:

We are given that an appliance manufacturer claims to have developed a compact microwave oven that consumes a mean of no more than 250 W with a population standard deviation of 15 W.

They take a sample of 20 microwave ovens and find that they consume a mean of 257.3 W.

Let \mu = <u><em>mean power consumption for microwave ovens.</em></u>

So, Null Hypothesis, H_0 : \mu \leq 250 W     {means that a compact microwave oven consumes a mean of no more than 250 W}

Alternate Hypothesis, H_A : \mu > 250 W     {means that a compact microwave oven consumes a mean of more than 250 W}

The test statistics that would be used here <u>One-sample z test statistics</u> as we know about the population standard deviation;

                                T.S. =  \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }  ~ N(0,1)

where, \bar X = sample mean power consumption for ovens = 257.3 W

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            n = sample of microwave ovens = 20

So, <em><u>the test statistics</u></em>  =  \frac{257.3-250}{\frac{15}{\sqrt{20} } }

                                      =  2.176

The value of z test statistics is 2.176.

<u>Now, at 0.05 significance level the z table gives critical value of 1.645 for right-tailed test.</u>

Since our test statistic is more than the critical value of t as 2.176 > 1.645, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which <u>we reject our null hypothesis</u>.

Therefore, we conclude that a compact microwave oven consumes a mean of more than 250 W.

7 0
3 years ago
Scrieți multipli lui 7 mai mari decât 10 și mai mici decât 20​
beks73 [17]
<h2>Helloooo!!! Marie Here!!!</h2><h2 />

The answer is here:

  • 7 . 2 = 14, 10 >14 > 50

  • 7 . 3 = 21, 10 > 21 > 50

  • 7 . 4 = 28, 10 > 28 > 50

  • 7 . 5 = 35, 10 > 35 > 50

  • 7 . 6 = 42, 10 > 42 > 50

<h3>Hope This Helps! Have A GREAT Day!</h3>

3 0
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