Question

PLEASE HELP!! The same numbers of each coin have a total of $6.00. There are nickles, dimes and quarters. How many of each coin are there? Pls solve algebraically.i will give the brainliest answer!

Answer 1

Answer:

Since there are the same amount we add all the values up.

Nickle = 0.05

Dime = 0.10

Quarter = 0.25

Add them all up

0.05 + 0.10 + 0.25 = 0.4

6 / 0.40 = 15

There is 15 of each coin

An equation would be 6 / (N + D + Q) = Answer

Hope this helps

Step-by-step explanation:

Answer 2

Answer: 15 of each coin

Step-by-step explanation:

So there are 3 types of coins and we know that there has to be the same number of coins. A nickle is worth 5, dime is 10, quarter is 25. So lets make an equation with the variable a. "A" equals the constant that each coin is multiplied by.

.5a + .10a + .25a = 6.00, lets solve for "a" now.

.40a = 6.00, then 6.00/.40 = 15

And there you go, there is 15 of each coin. Lets check if this is actually correct tho.

.5 x 15 = .75

.10 x 15 = 1.50

.25 x 15 = 3.75

.75 + 1.50 + 3.75 = 6.00