the scale on a map is 1in: 20mi is two cities are 5.5 inches apart on the map what ia the real distance between them

A phone company offers two monthly plans. Plan A costs $8 plus an additional $0.09 for each minute of calls. plan B cost $16 plu

harina [27]

Answer: 72

Plan A = 30 +0.15x

Plan B = 16 +0.20x

30+0.15x = 16+0.20x

subtract 16 from each side

14 +0.15x = 0.20x

subtract 0.15x from each side

14=0.05x

x = 14/0.05 = 280 minutes

280*0.15 = 42 +30 = $72

280 * 0.20 = 56 +16 = 72

280 minutes and cost $72 each

Step-by-step explanation:

5 0

3 years ago

a florist is preparing 10 vases for flowers and each vase will contain 3 roses and 8 carnations.How many of each type of flower

Bingel [31]

There’s 10 vases. Each one needs 3 roses and 8 carnations. So 3(10) is how many roses and 8(10) is how many carnations. The equation is 10(3x+8y) x being roses and y being carnations.

8 0

3 years ago

Sarah and Gabriela are at a soccer camp. The length of a soccer practice is 2/3 hour. The coaches have set aside 8 hours for soc

Nesterboy [21]

Answer:

12 soccer practices

Step-by-step explanation:

1 Soccer practice = 2 / 3 hour

We have 8 hours

8 / 2/3

multiply the top and bottom by 3 to get rid of the 3

8 * 3 = 24

2/3 * 3 = 2

24 / 2 = 12

4 0

3 years ago

Read 2 more answers

I need to solve for x.

sineoko [7]

Answer:

45 degress

Step-by-step explanation:

7 0

3 years ago

The transformation of 'f' is represented by 'g'. Write a rule for g. f(x)=\root(3)(x). Then show your check steps.

podryga [215]

Answer:

$g(x)=-2\sqrt[3]x$

or

$g(x) = -2f(x)$

Step-by-step explanation:

Given

$f(x) = \sqrt[3]x$

Required

Write a rule for g(x)

See attachment for grid

From the attachment, we have:

$(x_1,y_1) = (-1,2)$

$(x_2,y_2) = (1,-2)$

We can represent g(x) as:

$g(x) = n * f(x)$

So, we have:

$g(x) = n * \sqrt[3]x$

For:

$(x_1,y_1) = (-1,2)$

$2 = n * \sqrt[3]{-1}$

This gives:

$2 = n * -1$

Solve for n

$n = \frac{2}{-1}$

$n = -2$

To confirm this value of n, we make use of:

$(x_2,y_2) = (1,-2)$

So, we have:

$-2 = n * \sqrt[3]1$

This gives:

$-2 = n * 1$

Solve for n

$n = \frac{-2}{1}$

$n = -2$

Hence:

$g(x) = n * \sqrt[3]x$

$g(x)=-2\sqrt[3]x$

or:

$g(x) = -2f(x)$

4 0

3 years ago