Answer:
Circle 1=6x+2y
Rectangle 4 = 3x+y
Circle 4 = 5x
Step-by-step explanation:
4x+3y and 2x-y can be added to find result for the circle.
Let C1 represent circle 1
4x+3y+2x-y=C1\\
Combining\:like\:terms\\
4x+2x+3y-y=C1
6x+2y=C1
So, The result is: C1=6x+2y
Now, We need to solve:
Let R1 represent rectangle 4
x+4y + R1 = 4x+5y
R1=4x+5y-(x+4y)
R1=4x+5y-x-4y
R1=4x-x+5y-4y
R1=3x+y
So, Solving x+4y + R1 = 4x+5y, We get R1 = 3x+y
Now, We need to solve the equation:
Let C4= Circle 4
2x-y+3x+y=C4
Combining the like terms
2x+3x-y+y=C4
5x=C4
So, Solving 2x-y+3x+y=C4 we get C4 = 5x
Answer: (3, -1)
Step-by-step explanation:
y = |x-3|-1
When y=|x|, vertex is (0, 0).
Now, let's translate the graph so it becomes y = |x-3|-1.
|x| ==> |x-3| Translate the graph 3 units to the right
Vertex: (0+3, 0) ==> (3, 0)
|x-3| ==> |x-3|-1 Translate the graph 1 unit down
Vertex: (3, 0-1) ==> (3, -1)
Vertex: (3, -1)
Answer:
5
Step-by-step explanation:
Triangle ABD and ADC are righttriangles so u can use the Pythagorean theorem/triples. the triples are 3/4/5 and 5/12/13. 12 is 4x3, and 15 is 5x3, so BD is 3x3, which is 9. AC is 13, as it is part of the Pythagorean’s triples