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makkiz [27]
3 years ago
14

A byte consists of 8 bits. A kilobyte is 2^10 bytes. How many bits are in a kilobyte?

Mathematics
1 answer:
Furkat [3]3 years ago
8 0

Answer:

8,192 bits

Step-by-step explanation:

1. Determine how many bytes are in a kilobyte.

To do this, we simply need to get 2 to the tenth power (2 * 2 * 2 * 2 * 2 *2 * 2 * 2 * 2 * 2), which ends up being 1,024 bytes in one kilobyte.

2. Determine how many bits are in 1,024 bytes.

Since 1 byte = 8 bits, all we have to do is multiply 1,024 bytes by 8 bits, which leaves us with 8,192 bits.

Answer: 1 kilobyte = 8,192 bits

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Each output value is equal to the square of the input value minus<br> five
Ivenika [448]

i think that A pair of an input value and its corresponding output value is called an ordered pair and can be written as (a, b). In an ordered pair the first number, the input a, corresponds to the horizontal axis and the second number, the output b, corresponds to the vertical axis.

We can thus write our values as ordered pairs

(0, 0) - This ordered pair is also referred to as the origin

(1, 2.5)

(2, 5)

(3, 7.5)

These ordered pairs can then be plotted into a graph.

6 0
3 years ago
¡¡¡40 POINTS!!!HELP ASAP!!
Nataly_w [17]
Hi there!

To start, we can use the two points to find the slope using the formula y2-y1/x2-x1. Just sub in the points and solve!

-0.5-0.5/3-(-3)
-1/6
Sub that into the formula y-mx+b for m, and use one of the points for x and y - solve for b and you get your equation. 

y=mx+b
y=-1/6x+b
0.5=-1/6*-3+b
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Therefore your equation is y=-1/6x+1

Hope this helps!



8 0
3 years ago
Neptune is an average distance of 4.5 × 10^9 km from the Sun. Estimate the length of the Neptunian year using the fact that the
zlopas [31]

Answer:

Answer:

164.32 earth year

Step-by-step explanation:

distance of Neptune, Rn = 4.5 x 10^9 km

distance of earth, Re = 1.5 x 10^8 km

time period of earth, Te = 1 year

let the time period of Neptune is Tn.

According to the Kepler's third law

T² ∝ R³

\left ( \frac{T_{n}}{T_{e}} \right )^{2}=\left ( \frac{R_{n}}{R_{e}} \right )^{3}

\left ( \frac{T_{n}}{1} \right )^{2}=\left ( \frac{4.5\times10^{9}}}{1.5\times10^{8}}} \right )^{3}

Tn = 164.32 earth years

Thus, the neptune year is equal to 164.32 earth year.

Step-by-step explanation:

3 0
3 years ago
Someone help plz!!!
rewona [7]
20 I think good luck
4 0
3 years ago
Which of the following points lie on y-axis?
prohojiy [21]

Answer:

C (0,1)

D (0,0)

E (0,-1)

G (0,5)

Step-by-step explanation:

The x coordinate has to be a zero so that the point could be on the Y-axis

6 0
2 years ago
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