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3 years ago

3. Changing the opacity of the image and changing colors is a basic way of performing color correction. (1 point)

Mathematics

2 answers:

erma4kov [3.2K]3 years ago

6 0

The answer to the question is true

artcher [175]3 years ago

4 0

Answer: True

Step-by-step explanation: Just took the test

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<img src="https://tex.z-dn.net/?f=%28sinx%5E%7B2%7D%20theta%29%5Cfrac%7Bx%7D%7By%7D%281%2Bcostheata%29" id="TexFormula1" title="

beks73 [17]

The result of expanding the trigonometry expression $\sin^2(\theta) * (1 + \cos(\theta))$ is $cos^0(\theta) + \cos(\theta) - \cos^2(\theta) - \cos^3(\theta)$

<h3>How to evaluate the expression?</h3>

The expression is given as:

$\sin^2(\theta) * (1 + \cos(\theta))$

Express $\sin^2(\theta)$ as $1 - \cos^2(\theta)$ .

So, we have:

$\sin^2(\theta) * (1 + \cos(\theta)) = (1- \cos^2(\theta)) * (1 + \cos(\theta))$

Open the bracket

$\sin^2(\theta) * (1 + \cos(\theta)) = 1 + \cos(\theta) - \cos^2(\theta) - \cos^3(\theta)$

Express 1 as cos°(Ф)

$\sin^2(\theta) * (1 + \cos(\theta)) = cos^0(\theta) + \cos(\theta) - \cos^2(\theta) - \cos^3(\theta)$

Hence, the result of expanding the trigonometry expression $\sin^2(\theta) * (1 + \cos(\theta))$ is $cos^0(\theta) + \cos(\theta) - \cos^2(\theta) - \cos^3(\theta)$

Read more about trigonometry expressions at:

brainly.com/question/8120556

#SPJ1

3 0

2 years ago

The Jackson family drove 496 miles in 8 hours. Which is the unit rate in fraction form?

vagabundo [1.1K]

You find the unit rate by dividing 496 by 8
so
$\frac{496}{8} = \frac{62}{1}$

Hope I helped

3 0

3 years ago

Read 2 more answers

Last year 64 new houses were built in a neighborhood so far this year 7/8 of them have been sold how many new houses have been s

laiz [17]

Answer:

Step-by-step explanation:

for this problem you would first figure out what 1/8 of 64 is. 1/8 of 64 is 8.so we do 7*8 to get 56 so 56 of the 64 houses have been sold

6 0

2 years ago

Let a=x^2+4. Use a to find the solutions for the following equation:

Helga [31]

(x^2+4)^2 + 32 = 12x^2 + 48 .... a = x^2 + 4
(x^2 + 4)^2 + 32 = 12(x^2 + 4) 
a^2 + 32 = 12a 
a^2 - 12a + 32 = 0 
(a - 8)(a - 4) = 0 
a = 8 and a = 4 

for a = 8 ... 8 = x^2 + 4 ... x^2 = 4 ... x = +/- 2 
for a = 4 ... 4 = x^2 + 4 ... x^2 = 0 ... x = 0 

x = -2, 0, +2 so your answer is going to be e

4 0

3 years ago

Read 2 more answers

What is the midpoint between (3,5) and (7,9)

NikAS [45]

Your anbswer is gonna be 5,7

5 0

3 years ago

Read 2 more answers