X-int:let y=0
3x-2(0)=18
3x=18
divide both sides by 3
therefore x=6
y-int:let x=0
3(0)-2y=18
-2y=18
we divide both side by -2
therefore y=-9
A pentagon is a regular polygon with five equal sides and five equal interior angles. Also, it has five vertices. To draw the line that would divide the figure equally into two, we simply have to draw a line from one vertex and then extend the line to the opposite side.
Since, there are five vertices then, she will be able to draw five.
<em>Answer: 5</em>
Answer:
Step 1 should have a -2 substituted for both values.
1 to 3
Since you know that he landed on tails 8 out of 32 times, he must have flipped heads for the flips he did not flip tails. So, subtract 32 minus 8, which equals 24, and your answer is 8 to 24. Simplify this like you would with a fraction; the greatest common factor is 8 so divide the "numerator" and the "denominator" by 8. Therefore your final answer is 1 to 3.
1. Angles ADC and CDB are supplementary, thus
m∠ADC+m∠CDB=180°.
Since m∠ADC=115°, you have that m∠CDB=180°-115°=65°.
2. Triangle BCD is isosceles triangle, because it has two congruent sides CB and CD. The base of this triangle is segment BD. Angles that are adjacent to the base of isosceles triangle are congruent, then
m∠CDB=m∠CBD=65°.
The sum of the measures of interior angles of triangle is 180°, therefore,
m∠CDB+m∠CBD+m∠BCD=180° and
m∠BCD=180°-65°-65°=50°.
3. Triangle ABC is isosceles, with base BC. Then
m∠ABC=m∠ACB.
From the previous you have that m∠ABC=65° (angle ABC is exactly angle CBD). So
m∠ACB=65°.
4. Angles BCD and DCA together form angle ACB. This gives you
m∠ACB=m∠ACD+m∠BCD,
m∠ACD=65°-50°=15°.
Answer: 15°.
