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2 years ago

13

Triangle FGH is dilated agout the origin make triangle F'G'H' as shown here. Which rule represents the dilation applied to trian

gle FGH to create triangle F'G'H'?

1 answer:

elena-s [515]2 years ago

7 0

Answer:

Answer is J

Step-by-step explanation:

Count the height of each traingle and divide both of them, it's also going to be greater than 1X since the dialted image is larger than the original

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A red apple has mass of 20 grams .you cut it into 5 slices. what about the aplles has changed ?

Nutka1998 [239]

Well you have cut it into smaller pieces so it would be I guess 4 grams now because 20 divided by 5 is 4.

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3 years ago

A. 4.312 x 10 to the power of 2

son4ous [18]

Answer:

431.2

Step-by-step explanation:

hope this helps :3

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3 years ago

Read 2 more answers

Andrew has one book that is 237 inches thick and a second book that is 3.56 inches thick. If he stacks the books, about how tall

sattari [20]

You just add the thickness of the 2 books which is 237+3.56=240.56
Then you round the hundredth place which is 5 and next to it is the number 6 and that’s 5+ so it’s going up by a number. The answer is 240.6 inches tall. I tried explaining it well so sorry if you didn’t understand.

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3 years ago

A package of 5 crackers contains 205 Calories. How many Calories are in one cracker using a double number line

natulia [17]

Answer:

Step-by-step explanation:

since there are 205 calories in 5 crackers we can represent this as

205/5

we need to find how many calories are in one cracker, so lets take "x" as the # of calories in 1 cracker

so

$\frac{x}{1} =\frac{205}{5}$

cross multiply

5x=205

divide by 5 on both sides

x=41

41 calories in 1 cracker

Number line:

7 0

2 years ago

1. A hotel is in the shape of a cylinder, with a circular foundation. The circumference of the foundation is 2 times the radiu

AysviL [449]

2)The circumference or perimeter of a circle with radius $r$ is

$P=2\pi r$ . Given $P=28\pi$ . Therefore,

$2\pi r =28\pi \\ r=14\\ d=2r=28\\ A=\pi r^2 \\ A=\pi (14)^2\\ A=[tex] 196\pi$

Thus the radius is $14\;ft$ , diameter $28\;ft$ and area $196\pi \;ft^2$

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3 years ago