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3 years ago

15

If you begin investing at age 45 instead of age 40, how much more do you need to invest per month to have $retirement ? Why this

amount so much greater than the difference between 20 and 25?

1 answer:

seropon [69]3 years ago

7 0

Step-by-step explanation:

x566 ghdhdurhfudhdyehrv4 the answer is 566

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For a class trip, a total of 116 ticket need to be purchased. The cost of an adult ticket is $17000. The cost of a child ticket

zhuklara [117]

Answer:

the price of child tickets are 4,250. how many adult tickets were sold is 91. how many child tickets were sold is 25. which adds up to 1,653,250. your welcome.

Step-by-step explanation:

1,547,000 + 106,250 = 1,653,250

17000 - 12,750(75%) =4,250

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3 years ago

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3x² + 24 + 45=0<br> quadratic form

mylen [45]

Answer:

x = {3, 5}

Step-by-step explanation:

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If sin θ = cos 40°, 0<θ<90°, what is θ?

Bezzdna [24]

Answer:

θ = 50 degrees

Step-by-step explanation:

we have sin θ = cos 40°

θ = arcsin ( cos 40°)

and make sure θ is less than 90 and greater than 0

θ = arcsin (0.766044443)

θ = 50 degrees

3 0

3 years ago

If f(x)=x^2+3x+4 which of the number choices represents (f(x+h)-f(x))/h?

Helen [10]

In case you're not already aware, the expression $\frac{f(x+h)-f(x)}h$ is called the "difference quotient" and represents the average rate of change of a function $f$ over an interval $[x,x+h]$ .

For the function $f(x)=x^2+3x+4$ , by substituting $x+h$ we get

$f(x+h)=(x+h)^2+3(x+h)+4=(x^2+2xh+h^2)+(3x+3h)+4=x^2+3x+4+(2x+3)h+h^2$

Then the difference quotient is

$\dfrac{f(x+h)-f(x)}h=\dfrac{(x^2+3x+4+(2x+3)h+h^2)-(x^2+3x+4)}h$

$=\dfrac{(2x+3)h+h^2}h=2x+3+h$

where the last equality holds as long as $h\neq0$ .

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3 years ago

Do these ratios form a proportion? 26 medium hats to 2 small hats 39 medium hats to 3 small hats

inessss [21]

$\bf \cfrac{\textit{medium hats}}{\textit{small hats}}\qquad \qquad \cfrac{26}{2}=\cfrac{39}{13}\implies \cfrac{~~\begin{matrix} 2 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~\cdot 13}{~~\begin{matrix} 2 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}=\cfrac{~~\begin{matrix} 3 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~\cdot 13}{~~\begin{matrix} 3 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}\implies 13= 13~~\textit{\Large \checkmark}$

7 0

3 years ago

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