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3 years ago

15

If you begin investing at age 45 instead of age 40, how much more do you need to invest per month to have $retirement ? Why this

amount so much greater than the difference between 20 and 25?

1 answer:

seropon [69]3 years ago

7 0

Step-by-step explanation:

x566 ghdhdurhfudhdyehrv4 the answer is 566

You might be interested in

Write the following expression as a simplified polynomial in standard form.

LiRa [457]

Answer:

x^2-5x+33

Step-by-step explanation:

(x-4)^2 -5x+20-3

x^2-4^2

6 0

3 years ago

Last term of the arithmetic progression 8,15,22 is 218. Find<br>the number of terms.

icang [17]

Answer:

31 terms.

Step-by-step explanation:

218 = 8 + (n-1)7

210 = (n-1)7

30 + n-1

n = 31

There would be 31 terms in the given AP.

7 0

3 years ago

What is the equation of a line that is perpendicular to −x+2y=4 and passes through the point (−2, 1) ? Enter your equation in th

ANTONII [103]

Perpendicular lines have slopes that multiply to get -1
y=mx+b is the slope intercept equation
m=slope

so get into y=mx+b form
-x+2y=4
solve for y
add x both sides
2y=x+4
divide by 2 both sides
y=(1/2)x+2
the slope is 1/2

perppendicular line slope multiplies to -1
1/2 times what=-1
times 2/1 both sides
what=-2/1=-2

y=-2x+b
find b
we are given a point is (-2,1)
when x=-2, y=1
1=-2(-2)+b
1=4+b
minus 3 both sides
-3=b

so the equation is
y=-2x-3

your teacher might want it in standard form (ax+by=c) so
add 2x both sides
2x+y=-3 is an equation

so y=-2x-3 is correct (slope intercept form)
2x+y=-3 is also correct (standard form)

6 0

2 years ago

GIVING BRAINLIEST! A rectangular garden has a width of 10 feet and a length of 14 feet. A cement walkway is added around the out

Serjik [45]

Given:

Width of a garden = 10 feet

Length of the garden = 14 feet

Area of the garden and the walkway together = 396 square feet.

To find:

The width of the walkway.

Solution:

A cement walkway is added around the outside of the garden.

Let x be the width of the walkway.

The width of the garden with walkway = 10+2x

The length of the garden with walkway = 14+2x

Area of a rectangle is

$Area=length\times width$

Area of garden and the walkway together is

$Area=(14+2x)\times (10+2x)$

$396=140+28x+20x+4x^2$

$396=140+48x+4x^2$

$396=4(35+12x+x^2)$

Divide both sides by 4.

$99=35+12x+x^2$

$0=35-99+12x+x^2$

$0=-64+12x+x^2$

Splitting the middle term, we get

$x^2+16x-4x-64=0$

$x(x+16)-4(x+16)=0$

$(x+16)(x-4)=0$

Using zero product property, we get

$(x+16)=0\text{ and }(x-4)=0$

$x=-16\text{ and }x=4$

Width of walkway cannot be negative. So, x=4.

Therefore, the width of the walkways is 4 feet.

6 0

3 years ago

Read 2 more answers

Can someone help me figure out how to graph f(x)=5x-45

tatuchka [14]

Well since the exponent is 1 then the function given is a linear function so y=5x-45 will be a line with a slope of 5 and a y-intercept at (0,-45)

4 0

3 years ago