All categories

2 years ago

F(x)=x^2-2x+3; f(x)=-2x+28

Mathematics

1 answer:

adell [148]2 years ago

8 0

Answer:

(-5, 38) and

(5,18)

Step-by-step explanation:

$x^2-2x+3=-2x+28\\ x^2-2x+3+2x=28\\ x^2 = 28-3=25\\ x^2-25=0\\ x^2-5^2 =0\\ (x-5)(x+5)=0\\ x = 5 \ or \ x=-5$

so the solutions are

(-5, 38) and

(5,18)

You might be interested in

Please help me it needs to be correct

dimaraw [331]

Answer:

4(3m^3-2m^2+4m+2)

Step-by-step explanation:

6 0

2 years ago

Read 2 more answers

Beth can swim 2 laps in 7 minutes what is Beth rate in minutes per lap

Bond [772]

The answer is 1 lap/3.5 minutes

4 0

2 years ago

Read 2 more answers

Is angle SAM congruent to angle DEL if so identify the simularity postulate or theorem applies

atroni [7]

Answer:

yes

Step-by-step explanation:

yes because that is literally what he used

4 0

2 years ago

Use your understanding of the unit circle and trigonometric functions to find the values requested.

vfiekz [6]

Answer:

a) For this case we can use the fact that $sin (\pi/3) = \frac{\sqrt{3}}{2}$

And for this case since we ar einterested on $-\frac{\pi}{3}$ and we know that the if we are below the y axis the sine would be negative then:

$sin (-\pi/3) = -\frac{\sqrt{3}}{2}$

b) From definition we can use the fact that $tan x= \frac{sin x}{cos x}$ and we got this:

$tan (5\pi/4) = \frac{sin(5\pi/4)}{cos(5\pi/4)}$

We can use the notabl angle $\pi/4$ and we know that :

$sin (\pi/4) = cos(\pi/4) = \frac{\sqrt{2}}{2}$

Then we know that $5\pi/4$ correspond to 225 degrees and that correspond to the III quadrant, and we know that the sine and cosine are negative on this quadrant. So then we have this:

$tan (5\pi/4) = \frac{sin(5\pi/4)}{cos(5\pi/4)}= \frac{\frac{sqrt{2}}{2}}{\frac{\sqrt{2}}{2}} = 1$

Step-by-step explanation:

For this case we can use the notable angls given on the picture attached.

Part a

For this case we can use the fact that $sin (\pi/3) = \frac{\sqrt{3}}{2}$

And for this case since we ar einterested on $-\frac{\pi}{3}$ and we know that the if we are below the y axis the sine would be negative then:

$sin (-\pi/3) = -\frac{\sqrt{3}}{2}$

Part b

From definition we can use the fact that $tan x= \frac{sin x}{cos x}$ and we got this:

$tan (5\pi/4) = \frac{sin(5\pi/4)}{cos(5\pi/4)}$

We can use the notabl angle $\pi/4$ and we know that :

$sin (\pi/4) = cos(\pi/4) = \frac{\sqrt{2}}{2}$

Then we know that $5\pi/4$ correspond to 225 degrees and that correspond to the III quadrant, and we know that the sine and cosine are negative on this quadrant. So then we have this:

$tan (5\pi/4) = \frac{sin(5\pi/4)}{cos(5\pi/4)}= \frac{\frac{\sqrt{2}}{2}}{\frac{\sqrt{2}}{2}} = 1$

6 0

2 years ago

Please help me find the equation xx

Lisa [10]

9514 1404 393

Answer:

(2x-10) +x +(x+10) = 180
x = 45
(2x-10)° = 80°
(x+10)° = 55°
x° = 45°

Step-by-step explanation:

The equation is an expression of the fact that <em>the sum of the angles in a triangle is 180°.</em>

(2x -10)° +x° +(x +10)° = 180°

For the purposes of the answer box, I'd leave off the degree symbol:

(2x -10) +x +(x +10) = 180

This simplifies to ...

4x = 180

x = 45

Then the angles (CW from top) are ...

(2·45 -10) = 80°

(45 +10)° = 55°

(45)° = 45°

8 0

2 years ago