Answer:
Total length of iron needed to make the square frame and two diagonals = 43.44 in (Approx)
Step-by-step explanation:
Given:
Length of diagonal = 9 in
Find:
Total length of iron needed to make the square frame and two diagonals.
Computation:
Area of square = 1/2(diagonal)²
Area of square = 1/2(9)²
Area of square = 40.5 in²
Area of square = Side × Side
40.5 in² = Side × Side
Side = 6.36 (approx)
Total length of iron needed to make the square frame and two diagonals = Permeter of square + (2 × diagonal)
⇒ (4 × 6.36) + (2 × 9)
⇒ (25.44) + (18)
⇒ 43.44 in
Total length of iron needed to make the square frame and two diagonals = 43.44 in (Approx)
I think the answer you have there is correct
Answer:
122
Step-by-step explanation:
SA=2lw+2lh+2hw
SA = 2(7)(4) + 2(7)(3) + 2(3)(4)
SA = 122
Answer:
Length of the Rectangle = 10 inches
and Width = 25 inches
Step-by-step explanation:
Let the width of the rectangle = k inches
So, the Length of the rectangle = (3k - 5) inches
Perimeter = 70 inches
Now, Perimeter of the Rectangle = 2(Length + Width)
= 2 (k + (3k-5))
⇒ 2 (k + (3k-5)) = 70
or, 2(k + 3k -5) = 70 ⇒ 2(4k - 5) = 70
⇒ 8k - 10 = 70
or, 8k = 70+ 10 = 80
or, k = 80/8 = 10
So, the Length = 10 inches
Hence, Width = 3k - 5 = 3(10) - 5 = 30 - 5 = 25 inches
So, Length of the Rectangle = 10 inches
and Width = 25 inches
Answer:
Step-by-step explanation:
Let s be the number of students in each of 6 buses. Then there are 6s students in all buses.
Five of the students ride in a van. In total, in a van and in buses there are 
students.
There are 221 students on a filed trip. So,
