Write an expression to find the difference in the maximum area and minimum area of a nys high school soccer field. Then evaluate
the expression.
Max length 100yards
Max length 120 yards
Minimum width 55 yards
Maximum width 80 yards
1 answer:
The maximum area of the school soccer field is given by the maximum length times the maximum width.
Thus maximum area = 120 x 80 = 9,600 square yards.
The minimum area of the school soccer field is given by the minimum length times the minimum width.
Thus maximum area = 100 x 55 = 5,500 square yards.
Therefore, the difference between the maximum area and the minimum area is 9,600 - 5,500 = 4,100 square yards.
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number 9 =al you have to do is one and 7 eighths =9 so your sum will be 10 and 7 eighths.
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Exponent rule : a^-b = 1 / a^b
52^-5 =
1 / 52^5 =
1 / (52 * 52 * 52 * 52 * 52)
Answer:
Step-by-step explanation:
10+100=1000
20+100=2000
Answer:
This is not correct question