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4 years ago

F(x) = 384 + 48x What is the zero of f(x)

Mathematics

2 answers:

frozen [14]4 years ago

4 0

Answer:

its 22 .

Step-by-step explanation:

Anettt [7]4 years ago

3 0

Answer:

- 8

Step-by-step explanation:

f(x) = 384 + 48x

f(x) = 0 : 384 + 48x = 0

48x = - 384

x = -384 / 48 = - 8

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The equation of the quadratic function represented by the graph is y=a(x-3)^2-1. What is the value of a?

Y_Kistochka [10]

Answer:

Value of a is 2

Step-by-step explanation:

Given the equation of the quadratic function represented by the graph is $y=a(x-3)^2-1$ . we have to find the value of a.

As seen in the figure, parabola cuts the graph at point (2,1) implies point (2,1) is one of the solution of the given quadratic equation i.e of given parabola.

∴ Point (2,1) satisfies the given equation.

Hence, we can find the value of a by putting the value of x and y, we get

$1=a(2-3)^2-1$

⇒ $2=a$

Hence, the value of a is 2

5 0

3 years ago

Which equation represents f(x)?

JulijaS [17]

Function transformation involves changing the form of a function

The equation that represents the function f(x) is $f(x) = \sqrt[3] {x + 6} + 1$

<h3>How to determine the equation</h3>

The parent cube root function is:

$y = \sqrt[3] {x}$

When the function is translated 6 units left, the equation of the function becomes

$y = \sqrt[3] {x + 6}$

Next, the function is translated 1 unit up.

So, the equation of the function becomes

$y = \sqrt[3] {x + 6} + 1$

Express as a function

$f(x) = \sqrt[3] {x + 6} + 1$

Hence, the equation that represents the function f(x) is $f(x) = \sqrt[3] {x + 6} + 1$

Read more about function transformation at:

brainly.com/question/1548871

4 0

3 years ago

Please help: <br><br> 12x^4(-5/6x^3y^2)<br><br> If possible, include steps<br><br> Thanks.

tangare [24]

---------------------------------------------------------------------------------------
Question
---------------------------------------------------------------------------------------
$12x^4(- \frac{5}{6} x^3y^2)$

---------------------------------------------------------------------------------------
Multiply the constant: 12 x (-5/6)
---------------------------------------------------------------------------------------
$-10x^4( x^3y^2)$

---------------------------------------------------------------------------------------
Multiply the x (we add the power together when we multiply)
---------------------------------------------------------------------------------------
$-10x^7y^2$

---------------------------------------------------------------------------------------
Answer: -10x⁷y²
---------------------------------------------------------------------------------------

4 0

3 years ago

Please do all problems with work on paper thank you

damaskus [11]

a. $\frac{11}{12}$

b. $\frac{39}{20}$

c. $\frac{20}{21}$

Step-by-step explanation:

Step 1; First, we convert the given fractions into improper ones. To do this, we multiply the whole number with the denominator of the fraction and add with it the same fraction's numerator whereas the denominator remains unchanged. To convert the fraction

3 $\frac{1}{4}$ = (3 × 4) + 1 / 4 = $\frac{13}{4}$ ,

2 $\frac{1}{3}$ = (2 × 3) + 1 / 3 = $\frac{7}{3}$ ,

6 $\frac{1}{5}$ = (6 × 5) + 1 / 5 = $\frac{31}{5}$ ,

4 $\frac{1}{4}$ = (4 × 4) + 1 / 4 = $\frac{17}{4}$ ,

5 $\frac{2}{7}$ = (5 × 7) + 2 / 7 = $\frac{37}{7}$ ,

4 $\frac{1}{3}$ = (4 × 3) + 1 / 3 = $\frac{13}{3}$ .

Step 2; Now we subtract, using LCM to arrive at the answer

3 $\frac{1}{4}$ - 2 $\frac{1}{3}$ = $\frac{13}{4}$ - $\frac{7}{3}$ = $\frac{39-28}{12}$ = $\frac{11}{12}$ ,

6 $\frac{1}{5}$ - 4 $\frac{1}{4}$ = $\frac{31}{5}$ - $\frac{17}{4}$ = $\frac{124-85}{20}$ = $\frac{39}{20}$ ,

5 $\frac{2}{7}$ - 4 $\frac{1}{3}$ = $\frac{37}{7}$ - $\frac{13}{3}$ = $\frac{111-91}{21}$ = $\frac{20}{21}$ .

7 0

3 years ago

In a In a school of 567 pupils 278 are boys.

DIA [1.3K]

Answer:

49% of the pupils are boys and 51% are girls.

Step-by-step explanation:

Alright, so first, you've got to find the total number of students: 567.

Now, to find the value of 1%, you divide 567 by 100, which will give you 5.67.

Next, you divide the number of male students by the value of 1%. That's 278 ÷ 5.67 = 49.0299823633157.

Subtracting that from 100% gives you 50.9700176366843 (percentage of girls)

Now, you can't write all that down, so you'll round it! 49.0299823633157 will round down, because 0 is less than 5, so it's 49%. 50.9700176366843 rounds up, because 9 is greater than 5, so that's 51%.

Therefore, 49% of the pupils are boys and 51% are girls.

I hope this helps!

4 0

3 years ago