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zheka24 [161]
3 years ago
10

What is the greatest number of obtuse angles a triangle can contain?

Mathematics
2 answers:
NikAS [45]3 years ago
5 0
I think 1 because if you had 2 you'll end up with a shape that is greater than 180 degrees. Keep in mind obtuse angles a over 90 degrees. hope that helped
Gennadij [26K]3 years ago
3 0
Only one. Obtuse angles are greater than 90 degrees, and a triangle has interior angles that equal 180 degrees in total, so any more than one means interior angles greater than 180. Hope this helps!
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BARSIC [14]
Large boxes are 40 pounds.
Small boxes are 30 pounds.
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4 years ago
Show that the relation R consisting of all pairs(x, y)such that x and y are bit strings of length three or more that agree in th
Mice21 [21]

Answer:

See proof below

Step-by-step explanation:

An equivalence relation R satisfies

  • Reflexivity: for all x on the underlying set in which R is defined, (x,x)∈R, or xRx.
  • Symmetry: For all x,y, if xRy then yRx.
  • Transitivity: For all x,y,z, If xRy and yRz then xRz.

Let's check these properties: Let x,y,z be bit strings of length three or more

The first 3 bits of x are, of course, the same 3 bits of x, hence xRx.

If xRy, then then the 1st, 2nd and 3rd bits of x are the 1st, 2nd and 3rd bits of y respectively. Then y agrees with x on its first third bits (by symmetry of equality), hence yRx.

If xRy and yRz, x agrees with y on its first 3 bits and y agrees with z in its first 3 bits. Therefore x agrees with z in its first 3 bits (by transitivity of equality), hence xRz.

5 0
3 years ago
If the height is 12 inches and the diameter is 16 inches, what is the volume?
tigry1 [53]

Answer:

V = πr²h

V = π(8)^2×12 r = ½diameter= 16/2=8

V = 64π×12

V= 64 × 3.14 ×12

V = 2,411.52 cubic inches.

Hope it helps!

4 0
3 years ago
Bill draws a regular octagon with the perimeter of 32 units.He picks a vertex of the octagon and draws two line segments through
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3 years ago
Steven conjectures that for |x|>5, it is true that x^3>125. Is his conjecture correct? Why or why not?
vredina [299]

Conjectures are conclusions formed from evidences. Steven's conjecture that: x^3 > 125 is true because: x > 5 or x > -5 for |x| > 5

Given that:

|x| > 5

Split the inequality as follows:

x > 5 or x > -5

Take the cube of both sides

x^3 > 5^3 or x^3 > -5^3

Evaluate all exponents

x^3 > 125 or x^3 > -125

Steven's conjecture that: x^3 > 125 is true because:

x > 5 or x > -5 for |x| > 5

Read more about absolute inequalities at:

brainly.com/question/4688732

5 0
3 years ago
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