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3 years ago

Is 7th grade hard? Because I have so much anxiety and get so nervous for presentations!! Someone please help!

2 answers:

6 0

No worries! I'm heading into 7th as well! Just have a positive attitude and get on the good side of your teachers. Work really hard and have confidence and you will be fine. If there is a challenge you can talk to someone trusted like a counselor or adult and they can help you more.

dybincka [34]3 years ago

6 0

Nope 7th grade is a breeze but will feel challenging at the time. Stay true to yourself is the only advise I can give you

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Danielle's basic cell phone rate each month is $29.95. Add to that $5.95 for voice mail and $2.95 for text messaging. This past

kondor19780726 [428]

The answer o the question is $38.85.

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4 years ago

A carpenter needs to cut four sections, each 3–feet 8–inches long, from a piece of molding. If the board is only sold by the foo

KIM [24]

Alright, lets get started.

The length of each section what carpenter needs to cut is 3 feet and 8 inches.

Converting 3 feet and 8 inches into feet only, we know, $12 inches = 1 feet$

So, 3 feet 8 inches = $3 +\frac{8}{12} =3 +\frac{2}{3} =\frac{11}{3}$ feet

It means length of each section = $\frac{11}{3}$ feet

Carpenter needs to cut 4 sections, so length of 4 sections will be = $4*\frac{11}{3}=\frac{44}{3}=14\frac{2}{3} feet$

2/3 feet means 8 inches so she needs board 14 feet 8 inches

Board is only sold by the feet only so, she has to puchase 15 feet board. : Answer

Hope it will help :)

4 0

3 years ago

I need help ASAP with this pyramid scale factor question!

Brrunno [24]

Answer:

Step-by-step explanation:

because 14 is 7 x 2 the scale factor from the small pyramid to the big pyramid would be 1/2

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3 years ago

You made a square card. The card did not fit in the envelope so you trimmed it. You trimmed 4 inches from the length and 5 inche

ludmilkaskok [199]

Answer:

The original dimensions of the card were 9 inches length and 9 inches width

Step-by-step explanation:

Let x be the original length and width of the card in inches (remember that it was squared originally). The exercise says that the area of the new width, with dimensions x-4 and x-5 is 20 square inches, therefore

(x-4)*(x-5) = 20

x²-9x+20 = 20

x²-9x = 0

x*(x-9) = 0

x = 0 or x = 9

Since x must be positive, then it cant be 0, thus, x has to be 9. The original dimensions of the card were 9 inches length and 9 inches width.

7 0

4 years ago

Read 2 more answers

Perform the indicated operation and simplify the result 4x^3/3×(9/x)^3

STatiana [176]

The first thing we are going to do for this case is to rewrite the function correctly.
We have then:
$\frac{4x^3}{3} * (\frac{9}{x})^3$
For power properties we have:
$\frac{4x^3}{3} * \frac{9^3}{x^3}$
Canceling similar terms we have:
$\frac{4*9^3}{3}$
Doing the calculations we have:
$972$
Answer:
The result of the expression is:
A 972

4 0

3 years ago