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k0ka [10]
2 years ago
10

Drag a statement or reason to each box to complete this proof.

Mathematics
1 answer:
yanalaym [24]2 years ago
5 0

Answer: 2. Linear pair postulate

4. 60 + mACB=180

5. mACB=120

6. definition of obtuse angle

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URGENT I HAVE ALMOST 0 TIME LEFT I NEED LAST MINUTE HELP
jonny [76]

Answer:

The zeros are the points where the parabola intercepts the x-axis.

\sf x = 7 \implies x - 7 = 0

\sf x = 1 \implies x - 1 = 0

\sf \implies y = a(x - 7)(x - 1)  where a is some constant

If the parabola passes through point (3, 4) then:

\sf \implies a(3 - 7)(3 - 1) = 4

\sf \implies a(-4)(2) = 4

\sf \implies -8a = 4

\sf \implies a = -\dfrac12

So the equation of the parabola is:

\sf y = -\dfrac12(x - 7)(x - 1)

Or in standard form:

\sf y = -\dfrac12x^2+4x-\dfrac72

7 0
2 years ago
Candice drives a total of 48 miles each day to work and get back home. She works five days a week. Her car gets 21 miles per gal
slega [8]

Answer:

Total gallon of fuel used = 11.428 gallons

Step-by-step explanation:

Given -

The total distance travelled by car in one gallon of gas = 21 miles

Total distance travelled each day = 48 miles

Number of days days in a week in which Candice drive is 5 days

Total miles travelled per week = 48*5 = 240 miles

Total gallon of fuel used = \frac{240}{21} = 11.428 gallons

5 0
2 years ago
PLEASE HELP WITH MATH EASY
Marat540 [252]

Answer:

(2,4)

Step-by-step explanation:

the point where the lines intercept is the solution, so it is (2,4)

4 0
2 years ago
Read 2 more answers
Which answer describes the function f(x)=2x^3-x^2<br><br> Odd<br> Even<br> Neither
velikii [3]

it is neither, it cannot be raised to a power unless it is 0 or 1 :)

5 0
3 years ago
For what values of t on the interval [0, 21 ]is the instantaneous velocity positive​ (the projectile moves​ upward)?
OLEGan [10]

Answer:

0 <=t<=21

Step-by-step explanation:

Projectile is Moving upwards on an interval of (0 to 21), if we plot Velocity vs Time and denote positive y-axis above 0 and negative y-axis below  0(for velocity), then from 0 to 21 t projectile is moving upwards and has positive velocity, when the projectile reaches the top of it's motion and returns back down to ground it's velocity is negative and is plotted below the y =0 (note that is for t > 21).

hence for the interval 0 <=t <=21 the instantaneous velocity is positive (Note, instantaneous velocity is also the derivative of the velocity or the slope ).

8 0
3 years ago
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