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2 years ago

Drag a statement or reason to each box to complete this proof.

Mathematics

1 answer:

yanalaym [24]2 years ago

5 0

Answer: 2. Linear pair postulate

4. 60 + mACB=180

5. mACB=120

6. definition of obtuse angle

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$46.80 x 12?<br> im accually confused

777dan777 [17]

Answer:

$561.6

Step-by-step explanation:

You are basically multiplying 46.80 twelve times.

Hope this helps youuu ;)

6 0

3 years ago

Read 2 more answers

For a certain river, suppose the drought length Y is the number of consecutive time intervals in which the water supply remains

AnnZ [28]

Answer:

a) There is a 9% probability that a drought lasts exactly 3 intervals.

There is an 85.5% probability that a drought lasts at most 3 intervals.

b)There is a 14.5% probability that the length of a drought exceeds its mean value by at least one standard deviation

Step-by-step explanation:

The geometric distribution is the number of failures expected before you get a success in a series of Bernoulli trials.

It has the following probability density formula:

$f(x) = (1-p)^{x}p$

In which p is the probability of a success.

The mean of the geometric distribution is given by the following formula:

$\mu = \frac{1-p}{p}$

The standard deviation of the geometric distribution is given by the following formula:

$\sigma = \sqrt{\frac{1-p}{p^{2}}$

In this problem, we have that:

$p = 0.383$

$\mu = \frac{1-p}{p} = \frac{1-0.383}{0.383} = 1.61$

$\sigma = \sqrt{\frac{1-p}{p^{2}}} = \sqrt{\frac{1-0.383}{(0.383)^{2}}} = 2.05$

(a) What is the probability that a drought lasts exactly 3 intervals?

This is $f(3)$

$f(x) = (1-p)^{x}p$

$f(3) = (1-0.383)^{3}*(0.383)$

$f(3) = 0.09$

There is a 9% probability that a drought lasts exactly 3 intervals.

At most 3 intervals?

This is $P = f(0) + f(1) + f(2) + f(3)$

$f(x) = (1-p)^{x}p$

$f(0) = (1-0.383)^{0}*(0.383) = 0.383$

$f(1) = (1-0.383)^{1}*(0.383) = 0.236$

$f(2) = (1-0.383)^{2}*(0.383) = 0.146$

Previously in this exercise, we found that $f(3) = 0.09$

$P = f(0) + f(1) + f(2) + f(3) = 0.383 + 0.236 + 0.146 + 0.09 = 0.855$

There is an 85.5% probability that a drought lasts at most 3 intervals.

(b) What is the probability that the length of a drought exceeds its mean value by at least one standard deviation?

This is $P(X \geq \mu+\sigma) = P(X \geq 1.61 + 2.05) = P(X \geq 3.66) = P(X \geq 4)$ .

We are working with discrete data, so 3.66 is rounded up to 4.

Either a drought lasts at least four months, or it lasts at most thee. In a), we found that the probability that it lasts at most 3 months is 0.855. The sum of these probabilities is decimal 1. So:

$P(X \leq 3) + P(X \geq 4) = 1$

$0.855 + P(X \geq 4) = 1$

$P(X \geq 4) = 0.145$

There is a 14.5% probability that the length of a drought exceeds its mean value by at least one standard deviation

8 0

3 years ago

Plz help geometry will mark brainliest

stellarik [79]

15+16+10 =41
BH= 41
Bd=15
Df=16
Fh=10

Plz mark me brainalist answer

3 0

3 years ago

Find the measure of each bolded arc. Round to the nearest hundredth

vladimir1956 [14]

Answer:

Arc Length = 68.7

Step-by-step explanation:

The formula that is used to find the arc length:

s = (θ/360) * 2πr

(You would get the value of θ, by subtracting 57 from 360)

(You would get r by dividing 26 by 2)

Now we can solve this;

s = (303/360) 2π(13)

s = 0.842 * 2π(13)

s = 0.842 * 0.283(13)

s = 68.7

Hope this helps!

5 0

3 years ago

What’s the value of a ?

Mariulka [41]

Answer:

Step-by-step explanation: ccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccc

8 0

3 years ago