Drag a statement or reason to each box to complete this proof.

Find an equation of the line with an undefined slope and passes through the point (3, -4).

Hatshy [7]

Undefined means it goes through the x intercept, x=3

6 0

3 years ago

1.2 x + 4.6 > 54.6 − 0.8 x

Sedbober [7]

Answer:

look the photo

Step-by-step explanation:

..0000000000000000

3 0

3 years ago

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In the pictures down below<br><br>Can anyone help? Fractions and percents<br><br>

wariber [46]

1st Picture:
$3)- \frac{6}{7} +\frac {10}{11}
\\\\LCD:77
\\\\\frac{6}{7}* \frac{11}{11} + \frac{10}{11}*\frac{7}{7}= \frac{66}{77} + \frac{70}{77} = \frac{136}{77} = 1\frac{59}{77} 
 \\ \\ 4) 3\frac{6}{7}* 2 \frac{1}{10}= \frac{27}{7} * \frac{21}{10} = \frac{567}{70} =\frac{81}{10} = 8\frac{1}{10}
\\\\5)2\frac{1}{2}+3\frac{1}{3}
\\\\LCD: 6
\\\\ 2\frac{3}{6} + 3\frac{2}{6} =5\frac{5}{6}
\\\\6)5\frac{1}{8}*-6\frac{6}{11}=\frac{41}{8}* \frac{72}{11}=\frac{2952}{88}=\frac{369}{11}=33\frac{6}{11}$

2nd Picture:

$1)80 percent of 80 = .8*80 =64
\\\boxed{64}
\\\\2)95percent of 100=.95*100=95
\\\boxed{95}$

7 0

3 years ago

How would I do the steps to solve this?

allsm [11]

Answer:

The maximum revenue is 16000 dollars (at p = 40)

Step-by-step explanation:

One way to find the maximum value is derivatives. The first derivative is used to find where the slope of function will be zero.

Given function is:

$R(p) = -10p^2+800p$

Taking derivative wrt p

$\frac{d}{dp} (R(p) = \frac{d}{dp} (-10p^2+800p)\\R'(p) = -10 \frac{d}{dp} (p^2) +800 \ frac{d}{dp}(p)\\R'(p) = -10 (2p) +800(1)\\R'(p) = -20p+800\\$

Now putting R'(p) = 0

$-20p+800 = 0\\-20p = -800\\\frac{-20p}{-20} = \frac{-800}{-20}\\p = 40$

As p is is positive and the second derivative is -20, the function will have maximum value at p = 40

Putting p=40 in function

$R(40) = -10(40)^2 +800(40)\\= -10(1600) + 32000\\=-16000+32000\\=16000$

The maximum revenue is 16000 dollars (at p = 40)

3 0

3 years ago

Harry has a penny collection with 160 pennies. He plans to increase the size of his collection by a constant term each year for

mel-nik [20]

Answer:

A: Harry plans to have approximately 350 pennies at the end of the second year

B: Harry plans to have approximately 1,200 pennies at the end of his five-year plan.

C: Harry plans to increase his collection by approximately 1,050 pennies over the five-year period.

D: Harry will add approximately 250 pennies to his collenction d during the fourth year, according to his plan.

E: The coordinates of the point are (3.5, 400)

F: Harry will need to add approximately 150 more pennies more than what he had planned by the end of the fourth year, to get back on the plan.

Explanation:

The first thing I did was to write the numbers to the grid and add the points labeled with the letter of the question with which they are related.

Every mark on the x-axis corresponds to 1 year.

Every mark of the y-axis corresponds to 200 pennies.

See the graph attached.

Question A:

The y-coordinate of the green point labeled A is about half way between 300 and 400, i.e. 350.

Then, Harry plans to have approximately 350 pennies at the end of the second year

Question B:

The green point labeled B has coordinates (5, 1200), meaning that Harry plans to have approximately 1,200 pennies at the end of his five-year plan.

Question C:

Harry started his collection with approximately 150 coins. It is the y-coordinate (the value when x = 0): (200 - 100)/2 = 150.

Thus, Harry plans to increase his collection by approximately 1,200 - 150 = 1,050 pennies over the five-year period.

Question D:

The number of peenies that Harry will add to his collection during the fourth year, according to his plan, is the difference between the number of pennies at the end of the fourth year and the end of the third year.

The green point labeled D has coordinates (4, 800) meaning that his plan is to have approximately 800 pennies.

To find the number of pennies that Harry plans to have at the end of the third year read the y-coordinate that meets the curve when x = 3. That is approximately (600 + 500) / 2 = 550.

The difference is 800 - 550 = 250 pennies.

Therefore, Harry will add approximately 250 pennies to his collenction d during the fourth year, according to his plan.

Question E:

The blue point labeled E shows the position on the grid of the 400 pennies halfway throuhg the fourth year.

The coordinates of this point is (3.5, 400).

Question F:

According to the plan, the number of pennies at the end of the fourth year would be 800 (green point labeled D on the graph).

Then, Harry will need to add approximately 800 - 400 = 400 pennies.

According to the plan the number of coins at the end of the third year would be

But the plan was to add 800 - 550 = 250.

Thus, Harry will need to add 400 - 250 = 150 more pennies than he had planned, during the fourth year.

7 0

3 years ago

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