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Lina20 [59]
3 years ago
11

Si un empresario paga diariamente 50 a cada trabajador le faltaria 110 pero si les pagara 45 le sobraria 60 cuantos trabajadores

tiene dicho empresario
Mathematics
1 answer:
N76 [4]3 years ago
7 0

Answer:

34 trabajadores.

Step-by-step explanation:

Supongamos que el empresario tiene N trabajadores, y tiene la cantidad de dinero D para pagarles cada día.

Si el empresario decide pagarle 50 a cada trabajador le faltan 110.

Esto se puede reescribir como:

50*N = D + 110

(50 por número de empleados es igual que el dinero que tiene más lo que le falta para pagar)

También sabemos que si pagara 45 a cada empleado, le sobraría 60.

Esto se puede reescribir como:

45*N = D - 60

Entonces tenemos dos ecuaciones:

50*N = D + 110

45*N = D - 60

Para resolver esto, el primer paso es aislar una de las variables en una de las ecuaciones, en este caso aislaré D en la segunda ecuación.

45*N + 60 = D

Ahora podemos reemplazar esto en la primer ecuación y resolver para N

50*N = (45*N + 60) + 110

50*N = 45*N + 170

50*N - 45*N = 170

5*N = 170

N = 170/5 = 34

El empresario tiene 34 trabajadores.

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Answer:

the question is confusing but the answer is 2010

Step-by-step explanation:

because in the year 2000 it was

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4 0
3 years ago
M = 2; b=3 using y-intercept how do i solve
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The slope-intercept form:

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We have m = 2 and b = 3. Substitute:

y=2x+3

6 0
3 years ago
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Daniel [21]

Answer:

x < 5

Step-by-step explanation:

Step 1: Simplify

7x−35<2x−10

Step 2: Substract 2x from both sides

7x−35−2x<2x−10−2x

5x−35<−10

Step 3: Add 35 to both sides

5x−35+35<−10+35

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8 0
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Read 2 more answers
) An instructor gives his class a set of 18 problems with the information that the next quiz will consist of a random selection
RSB [31]

Answer:

The probability the he or she will answer correctly is 1.5%

Step-by-step explanation:

In all, there are 18 problems. In this question, the order of which the problems are sorted for the quiz makes no difference. For example, if the question A of the quiz is P1 and question B P2, and question A P2 and question B P1, it is the same thing.

There are 18 problems and 9 are going to be selected. So, there is going to be a combination of 9 elements from a set of 18 elements.

A combination of n elements from a set of m objects has the following formula:

C_{(m,n)} = \frac{m!}{n!(m-n)!}

In this question, m = 18, n = 9. So the total number of possibilities is:

T_{p} = C_{(18,9)} = \frac{18!}{9!(18-9)!} = 48620

Now we have to calculate the number of desired outcomes. This number is a combination of 9 elements from a set of 13 elements(13 is the number of problems that the student has figured out how to do).

Now, m = 13, n = 9. The number of desired possibilities is:

D_{p} = C_{(13,9)} = \frac{13!}{9!(13-9)!} = 715

The probability is the number of desired possibilities divided by the number of total possibilities. So

P = \frac{715}{48620} = 0.015 = 1.5%

The probability the he or she will answer correctly is 1.5%

3 0
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Answer:

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c = \sqrt{a^2+b^2}

The distance formula, gives an equivalent expression based on two points at the end of the hypotenuse for a triangle.

d^2 = (x_{2} -x_{1})^2 + (y_{2} -y_{1})^2

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