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Savatey [412]
3 years ago
15

The height of a square pyramid-shaped gift box is one half the length of

Mathematics
1 answer:
Schach [20]3 years ago
5 0

Answer:

15 inches

Step-by-step explanation:

Volume of a squre based pyramid :

V = a²(h/3)

a = base edge ; h = height

h =1/2 a

V = 4500

4500 = a² * (1/2a) ÷ 3

4500 = a² * a/2 * 1/3

4500 = a³/2 * 1/3

4500 = a³ / 6

27000 = a³

27000 = a³

Take the cube root of both sides

(27000)⅓ = a

30 = a

Recall:

h = 1/2a

h = 1/2(30)

h = 15 inches

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Two 5-year girls, Alyse and Jocelyn, have been training to run a 1-mile race. Alyse's 1 mile time A is approximately Normally di
tatyana61 [14]

Answer:

1.7 × 10⁻⁴

Step-by-step explanation:

The question relates to a two sample z-test for the comparison between the means of the two samples  

The null hypothesis is H₀:  μ₁ ≤ μ₂

The alternative hypothesis is Hₐ: μ₁ > μ₂

z=\dfrac{(\bar{x}_1-\bar{x}_2)-(\mu_{1}-\mu _{2} )}{\sqrt{\dfrac{\sigma_{1}^{2} }{n_{1}}-\dfrac{\sigma _{2}^{2}}{n_{2}}}}

Where;

\bar {x}_1 = 13.5

\bar {x}_2 = 12

σ₁ = 2.5

σ₂ = 1.5

We set our α level at 0.05

Therefore, our critical z = ± 1.96

For n₁ = n₂ = 23, we have;

z=\dfrac{(13.5-12)-(0)}{\sqrt{\dfrac{2.5^{2} }{23}-\dfrac{1.5^{2}}{23}}} = 3.5969

We reject the null hypothesis at α = 0.05, as our z-value, 3.5969 is larger than the critical z, 1.96 or mathematically, since 3.5969 > 1.96

Therefore, there is enough statistical evidence to suggest that Alyse time is larger than Jocelyn in a 1 mile race on a randomly select day and the probability that Alyse has a larger time than Jocelyn is 0.99983

Therefore;

The probability that Alyse has a smaller time than Jocelyn is 1 - 0.99983 = 0.00017 = 1.7 × 10⁻⁴.

8 0
3 years ago
NEED HELP ASAP What is true about the points on the graph of Y=3^x?
galben [10]

Answer:

d

Step-by-step explanation:

The answe of this question is d

3 0
3 years ago
A local water park has two types of season passes. Plan A costs a one-time fee of $125 for admission plus $8 for parking every t
Margarita [4]

Answer:

40+8X=50+23X

8X-23X=50-140

-15X=-90

X=-90/-15

X=7 TRIPS IS THE ANSWER.

PROOF:

140+8*6=50+23*6

140+48=50+138

188=188

4 0
3 years ago
During a business trip, an individual stopped at two rest stops. In the parking lot of the first rest stop, they counted 20 cars
olganol [36]

Answer

given,

on first stop

number of car = 20  and number of trucks = 18

on second stop

number of car = 18  and number of trucks = 10

we need to calculate which rest stop has higher ratio of car to truck.

Rest Stop 1

ratio= r₁ =\dfrac{cars}{trucks}

           r₁ =\dfrac{20}{18}

           r₁ =\dfrac{10}{9}

Rest Stop 2

ratio= r₂ =\dfrac{cars}{trucks}

           r₂ =\dfrac{18}{10}

           r₂=\dfrac{9}{5}

hence, r₂ > r₁

rest stop 2 has more car to truck ratio than rest stop 1

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3 years ago
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faltersainse [42]
Opposite sides of a parallelogram are congruent.
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Subtract 3x from both sides
2= x -3
Add 3 to both sides
5= x

2y+7=4y-9
Subtract 2y from both sides
7= 2y -9
Add 9 to both sides
16 = 2y
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8 = y
8 0
3 years ago
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