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spayn [35]
3 years ago
10

If f(x) = 7x^2 - 3x +1 and g(x) = 3x - 2, find the following by matching.

Mathematics
1 answer:
Cloud [144]3 years ago
4 0

f(x) = 7x² - 3x + 1

g(x) = 3x - 2


1. g(0) This means that x is 0, so you can plug in 0 for x in the equation:

g(x) = 3x - 2

g(0) = 3(0) - 2

g(0) = -2


2. g(1)    x is 1

g(x) = 3x - 2

g(1) = 3(1) - 2

g(1) = 3 - 2

g(1) = 1


3. f(1)     x is 1

f(x) = 7x²- 3x + 1

f(1) = 7(1)² - 3(1) + 1

f(1) = 7 - 3 + 1

f(1) = 5


4. f(x) = 7x²- 3x + 1

f(-2) = 7(-2)²- 3(-2) + 1

f(-2) = 7(4) + 6 + 1

f(-2) = 28 + 7

f(-2) = 35

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WUCLUJ
mash [69]

Answer:

81 degrees

Step-by-step explanation:

A quadrilateral has four interior angles which sum up to 360 degrees.

As we are given that two angles are right angles which means the sum of two angles will be 180 degrees and the third angle is 99 degrees.

As we know that the four angles sum up to 360 degrees.

Let A,B,C and D denote the four angles,

Then

Sum of angles = 360

A+B+C+D=360

90+90+99+D=360

279+D=360

D=360-279

D= 81 degrees

So the fourth angle is 81 degrees ..

7 0
3 years ago
Can someone perz help
storchak [24]
A is the correct answer cause you get heads twice as often as tails
7 0
3 years ago
Read 2 more answers
Find domain of y=rad20-6x
Evgesh-ka [11]
Domain, on an "even root" context, means, an even root cannot have a negative radicand, since  say for example \bf \sqrt{-25}\ne -5\qquad why?\implies (-5)(-5)=25

so... you end up with an "imaginary value"

so... for the case of 20-6x
"x", the domain, or INPUT
can afford to have any value, so long it doesn't make the radicand negative

to check for that, let us make the expression to 0, and see what is "x" then

\bf 20-6x=0\implies 20=6x\implies \cfrac{20}{6}=x\implies \cfrac{10}{3}=x

now, if "x" is 10/3, let's see \bf \sqrt{20-6\left( \frac{10}{3} \right)}\implies \sqrt{20-20}\implies \sqrt{0}\implies 0

now, 0 is not negative, so the radicand is golden

BUT, if "x" has a value higher than 10/3, the radicand turns negative
for example  \bf x=\frac{11}{3}
\\\\\\

\sqrt{20-6\left( \frac{11}{3} \right)}\implies \sqrt{20-22}\implies \sqrt{-2}

so.. that's not a good value for "x"

thus, the domain, or values "x" can safely take on, are all real numbers from 10/3 onwards, or to infinity if you wish
5 0
3 years ago
Algebra help - please be so kind - god bless. 2&3 please
azamat
2. -11 sq rt of 112
Sq rt of 16 times sq rt of 7
Becomes 4 sq rt of 7
Multiply -11 times 4 sq rt of 7
-44 sq rt of 7
Answer A


3. Subtract 17-9 since they are hitch the same sq rt

Answer 8 sq rt of 17
4 0
3 years ago
Solve the following linear equation for x<br><br> 5x - 2 + x = 9 + 3x + 10
Angelina_Jolie [31]

Answer:

x = 7

Step-by-step explanation:

5x - 2 + x = 9 + 3x + 10

6x - 2 = 9 + 3x + 10

6x - 2 = 3x + 19

6x = 3x + 21

3x = 21

x = 7

4 0
2 years ago
Read 2 more answers
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