Subtract. (3x^2+2x−9)−(4x^2−6x+3) Enter your answer, in standard form, in the box.
2 answers:
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Answer:
Option A.
Step-by-step explanation:
The given question is incomplete. Here is the complete question.
P(n) models the price (in dollars) of a pack of n bulbs at a certain store.
When does the price of a pack increase faster ?
n 4 10 12
P(n) 12 25 28
When does the price of a pack increase faster ?
A. Between 4 and 10 bulbs
B. Between 10 and 12 bulbs
C. The price increases at the same rat over both the intervals.
To solve this question we will find the rate of increase in the prices per pack in the given intervals.
From n = 4 to n = 10
Rate of increase in price =
=
= 2.166 ≈ $2.17 per pack
From n = 10 to n = 12
Rate of increase in price =
=
= $1.5 per pack
Therefore, price per pack increases faster between n = 4 and n = 10 as compared to n = 10 to n = 12.
Option A is the answer.
Answer:
B and C
Step-by-step explanation:
- The answer in the attached file
