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aksik [14]
3 years ago
6

Please help me, please I need a lot of help me is failing

Mathematics
2 answers:
Irina18 [472]3 years ago
8 0
I worked up and down btw
1. Yes
2. No
3. No
4. No
5. No
6. Yes
Crank3 years ago
6 0
1. Yes
2. No
3. No
4. No
5. No
6. Yes
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If u answer corectly (i know the answer already) ill paypal u 3 dollars
Helen [10]

Answer:

Park A

Step-by-step explanation:

Park b in decimal: 17 ÷ 8 = 2.125 miles

Park A is closer

7 0
3 years ago
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What is the total surface area of the cylinder to the nearest square inch ? Use 3.14 for pi
slamgirl [31]

Answer:

1,300.62

Step-by-step explanation:

The formula for a cylinder is A= 2 pi r h +2 pi r^2

7 0
3 years ago
What is a possible situation for this graph
vichka [17]
Y=40x since y intercept is 0 and slope is 40
8 0
3 years ago
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. The prime numbers p, q, r satisfy the simultaneous equations
Allisa [31]
Pq + pr = 80  => p (q+r) = 80
pq + qr = 425 => q (p+r ) = 425

Factorize 80 with having one factor as prime number
80 =  2 * 40 = 5 *16 

Factrorize 425 with having one factor as prime number
425 = 5 * 85 = 17 * 25...

Therfore, p has to be 2.
q = 17 and r= 23...
p + q +r = 2 + 17+ 23 = 42
3 0
3 years ago
Read 2 more answers
How do find the domain and range of <img src="https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B%5Csqrt%7Bx-8%7D%7D" id="TexFormula1" tit
Kisachek [45]
\sqrt{x-8} is undefined if the argument x-8 is negative, so you first need to require that

x-8\ge0\implies x\ge8

We're not done yet, though, because \dfrac1{\sqrt{x-8}} still doesn't exist when x=8, so we remove this from the domain and we're left with x>8, or in interval notation, (8,\infty)

To find the range, consider the limits of the function as you approach either endpoint of the domain.

\displaystyle\lim_{x\to8^+}\frac1{\sqrt{x-8}}=+\infty
\displaystyle\lim_{x\to\infty}\frac1{\sqrt{x-8}}=0

Since \dfrac1{\sqrt{x-8}} is positive everywhere, the range is (0,\infty)
3 0
3 years ago
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