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GenaCL600 [577]
3 years ago
15

Use the equation P=10-2.5c find P when c=3.2

Mathematics
2 answers:
satela [25.4K]3 years ago
6 0

Answer:

p = 2

Explanation:

Insert 3.2 for c

p = 10 − (2.5)(3.2)

Simplify both sides of the equation

p = 10 − (2.5)(3.2)

p = 10 + −8

p = (10 + −8) (Combine Like Terms)

p = 2

Svet_ta [14]3 years ago
6 0

Answer: P=2

Step-by-step explanation:

  1. Plug in 3.2 to -2.5c [10-2.5(3.2)]
  2. Multiply -2.5 & 3.2 ang get -8
  3. Do subtraction (10-8)
  4. P=2
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a standard six sided die. Janice rolled either a 2 or a 5 on the last 6 rolls of the die. What is the probability of Janice roll
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We have that   the probability of Janice rolling a 2 or 5 on her 7th toss of the dice is

\frac{1}{3}^7.

From the question we are told that

Janice rolled either a 2 or a 5 on the last 6 rolls of the die

Janice rolling a 2 or 5 on her 7th toss of the dice

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2 years ago
guse lagrange multipliers to find the maximum or minimum values of the function subject to the given constraint. (if an answer d
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Therefore the maximum value of function f(x,y,z)=x^{2} y^{2} z^{2} =1/27

And the minimum value is 0

<h3>What is function?</h3>

function, in mathematics, an expression, rule, or law that defines a relationship between one variable (the independent variable) and another variable (the dependent variable) (the dependent variable) (the dependent variable) (the dependent variable). Mathematics uses functions frequently, and functions are essential for specifying physical relationships in the sciences.

Here,

The function is given as:

f(x,y,z)=x^{2} y^{2} z^{2}

x^{2} +y^{2}+ z^{2}=1

=>x^{2} +y^{2}+ z^{2}-1=0

Using Lagrange multiplies, we have:

L(x,y,z,λ)=f(x,y,z) +λ(0)

Substitute f(x,y,z)=x^{2} y^{2} z^{2}  and x^{2} +y^{2}+ z^{2}-1=0

Differentiate

L(x)=2xy^{2} z^{2}+2λx

L(y)=2yx^{2} z^{2}+2λy

L(z)=2zx^{2} y^{2}+2λz

L(λ)=x^{2} +y^{2}+ z^{2}-1

Equating to 0

2xy^{2} z^{2}+2λx =0

2yx^{2} z^{2}+2λy = 0

2zx^{2} y^{2}+2λz = 0

x^{2} +y^{2}+ z^{2}-1 = 0

Factorize the above expressions

2xy^{2} z^{2}+2λx =0

2x(y^{2} z^{2}+λ)=0

2x=0 and (y^{2} z^{2}+λ)=0

x=0 and  y^{2} z^{2}= -λ

2yx^{2} z^{2}+2λy = 0

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2y=0 and (x^{2} z^{2}+λ)=0

y=0 and  x^{2} z^{2}= -λ

2zx^{2} y^{2}+2λz = 0

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2z=0 and (x^{2} y^{2}+λ)=0

z=0 and  x^{2} y^{2}= -λ

So we have ,

x=0 and  y^{2} z^{2}= -λ

y=0 and  x^{2} z^{2}= -λ

z=0 and  x^{2} y^{2}= -λ

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