2.25(a+1.3)=20.7 what is the value of a ?

Mathematics

1 answer:

Gnom [1K]3 years ago

4 0

Answer:

7.9

Step-by-step explanation:

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Solve 8[7-(6x-6)]+6x=0.

zavuch27 [327]

I believe that X would be -2.47619.
First you distribute the -1 in front of the parenthesis. Then distribute the 8 outside of the bracts. And finally just solve for X by combing like terms.

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3 years ago

Help plz : 4x-2(x-3)=10+(-9)

Dominik [7]

Distribute -2(x - 3)

4x - 2x + 6 = 10 + -9

Simplify

2x = -5

x = -2.5

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3 years ago

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Answer:

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Step-by-step explanation:

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2 years ago

A large farm has 75 acres of wheat and 62.5 acres of corn. The farm crew can harvest the wheat from 12 acres and the corn from 1

MAVERICK [17]

The answer for either field being harvested is 6.25 days (acres/(rate of harvest))
The answer is probably seven because, even though a day can be divided into parts, the fields are done the seventh not the sixth. (I'm assuming the problem calls for whole days)

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2 years ago

Find the radius of convergence, r, of the series. ∞ xn 2n − 1 n = 1 r = 1 find the interval, i, of convergence of the series. (e

Bingel [31]

Assuming the series is

$\displaystyle\sum_{n\ge1}\frac{x^n}{2n-1}$

The series will converge if

$\displaystyle\lim_{n\to\infty}\left|\frac{\frac{x^{n+1}}{2(n+1)-1}}{\frac{x^n}{2n-1}}\right|$

We have

$\displaystyle\lim_{n\to\infty}\left|\frac{\frac{x^{n+1}}{2(n+1)-1}}{\frac{x^n}{2n-1}}\right|=|x|\lim_{n\to\infty}\frac{\frac1{2n+1}}{\frac1{2n-1}}=|x|-\lim_{n\to\infty}\frac{2n-1}{2n+1}=|x|$

So the series will certainly converge if $-1$ , but we also need to check the endpoints of the interval.

If $x=1$ , then the series is a scaled harmonic series, which we know diverges.

On the other hand, if $x=-1$ , by the alternating series test we can show that the series converges, since

$\left|\dfrac{(-1)^n}{2n-1}\right|=\dfrac1{2n-1}\to0$

and is strictly decreasing.

So, the interval of convergence for the series is $-1\le x$ .

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3 years ago

2.25(a+1.3)=20.7 what is the value of a ? ​

2.25(a+1.3)=20.7 what is the value of a ?