A ball is thrown into the air with an upward velocity of 36 ft/s. Its height h in feet after t seconds is given by the function

2 answers:

8 0

H = - 16 t² + 36 t + 10
The maximum height of the ball is at the vertex of the parabola.
t = - b / 2 a
t = -36/-32
t = 1.12 s
The maximum height of the ball:
h max = - 16 * 1.12² + 32* 1.12 + 10 = - 16 * 1.2544 + 35.84 + 10 =
= - 20.0704 + 45.84 = 25.7696 = 25.77 m

Elza [17]3 years ago

5 0

Answer:

25.77 m

Step-by-step explanation:

The maximum height of the ball:

h max = - 16 * 1.12² + 32* 1.12 + 10 = - 16 * 1.2544 + 35.84 + 10 =

= - 20.0704 + 45.84 = 25.7696 = 25.77 m

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A machine covers 5/8 square foot in 1/4 hour

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The question is incomplete. Here is the complete question:

A machine covers 5/8 square foot in 1/4 hour. what is the unit rate?

Answer:

2.5 square feet per hour

Step-by-step explanation:

Given:

Area covered by a machine = $frac{5}{8}\ ft^2$

Time taken to cover the given area = $\frac{1}{4}\ h$

Now, unit rate of the first quantity with respect to second quantity is the magnitude of the first quantity being when the second quantity is one unit.

Here, the first quantity is the area covered and the second quantity is the time taken.

So, unit rate is the area covered by the machine in 1 hour.

In order to find that, we use the unitary method and divide the area by the total time taken. Therefore,

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