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bagirrra123 [75]
2 years ago
15

The splitting apart of one cell to form two new cells is called

Mathematics
1 answer:
Rzqust [24]2 years ago
7 0
The answer is A) Mitosis
You might be interested in
translate this verbal expression to a algebraic expression eight more than six times a number added to one more than nine times
34kurt
I will right it sideways. you can use this strategy later on if you would like. I put (parentheses) around what is optional to include. the = to the left of the second word number is to show that the number is equal. if there are two different variables you would put a crossed out equal sign.
_______________
eight= 8 l
more than= +
six= 6
times= x
(a)number= n l
_______________
added (to)= +
_______________
one= 1 l
more than= +
= number= n l
_______________

(I tried to do parentheses)

then, you rewrite what you wrote beside the words!

(8+6n)+(1+n)

that is your equation!
7 0
3 years ago
FIND THE EXACT AREA PLEASE HELPPPP ILL GIVE BRAINLIESTTTT
Ede4ka [16]

Answer:

555.94

Step-by-step explanation:

16 x 11 = 176/2

88

since there are two of the same triangle

88 x 2

176

11 is the radius

A = \pix^{2}

A = 3.14 ( pie is 3.14, if not then pi) x (11x11)

A = 3.14 x 121 (or 121\pi)

A = 379.94

379.94 + 176 (or 121pi + 176)

555.94

4 0
2 years ago
Find elapsed time 7:30am to 3:00 pm
Vikki [24]

Answer:

<u><em>7 hours 30 minutes and 0 Seconds</em></u>

Step-by-step explanation:

  • <em>60 minutes in 1 hour</em>
  • <em>7:30 - 3:00</em>
  • <em>60 * 10 = 600 Seconds</em>
  • <em>Plus the 30 minutes which converts to 20 seconds</em>
  • <em>Change that into hours and minutes</em>
7 0
1 year ago
The time that it takes a randomly selected job applicant to perform a certain task has a distribution that can be approximated b
storchak [24]

Answer:

A task time of 177.125s qualify individuals for such training.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by

Z = \frac{X - \mu}{\sigma}

After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X. Subtracting 1 by the pvalue, we This p-value is the probability that the value of the measure is greater than X.

In this problem, we have that:

A distribution that can be approximated by a normal distribution with a mean value of 145 sec and a standard deviation of 25 sec, so \mu = 145, \sigma = 25.

The fastest 10% are to be given advanced training. What task times qualify individuals for such training?

This is the value of X when Z has a pvalue of 0.90.

Z has a pvalue of 0.90 when it is between 1.28 and 1.29. So we want to find X when Z = 1.285.

So

Z = \frac{X - \mu}{\sigma}

1.285 = \frac{X - 145}{25}

X - 145 = 32.125

X = 177.125

A task time of 177.125s qualify individuals for such training.

7 0
3 years ago
What is the product? 5/9 × 3
Dmitry_Shevchenko [17]
<span>The answer is1.66666666667</span>
8 0
3 years ago
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