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Ostrovityanka [42]
2 years ago
10

Polygon a b c d is shown with exterior angles. exterior angle a is 25 degrees, exterior angle b is 146 degrees, and exterior ang

le d is 149 degrees. what is the measure of angle bcd? 25º 40º 140º 155º
Mathematics
1 answer:
Kaylis [27]2 years ago
8 0

The measure of angle bcd of the polygon abcd is 40°.

Hence, option b) 40° is the correct answer.

<h3>What is a polygon?</h3>

A polygon is simply a two-dimensional a plane shape enclosed by line segments called sides.

The sum of the exterior angles of a regular polygon will always equal 360

Given that;

  • Exterior angle a = 25 degrees
  • Exterior angle b =  146 degrees
  • Exterior angle d = 149 degrees
  • Exterior angle c = ?

25° + 146° + 149° + c = 360°

320° + c = 360°

c = 360° - 320°

c = 40°

The measure of angle bcd of the polygon abcd is 40°.

Hence, option b) 40° is the correct answer.

Learn more about polygons here: brainly.com/question/22408868

#SPJ4

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In ΔPQR, point C is the centroid. If PZ = 7, then RZ =<br> A) 3.5 <br> B) 7 <br> C) 14 <br> D) 21
kvv77 [185]

Answer: It's 7

Step-by-step explanation:

4 0
3 years ago
Solve x2 – 8x + 15 &lt; 0.<br><br> Select the critical points for the inequality shown.
quester [9]

Answer:

x=3,5

Explanation:

x2−8x+15=0

Try to express the terms of the equation in square form.

Adding 16 both sides of the equation,

(x2−2⋅x⋅4+42)+15=16

or,(x−4)2+15−16=0

or,(x−4)2−1=0

or,(x−4)2−12=0

This is the a2−b2=(a+b)(a−b)form.

(x−4+1)(x−4−1)=0

or,(x−3)(x−5)=0

Now, equate both the terms to zero since both of them when multiplied, give zero.

Either,

x−3=0

∴x=3

Or,

x−5=0

∴x=5

Ans:x=3,5 Hope this helpsXD...!!

4 0
3 years ago
Read 2 more answers
What is the value of the digit 4 in 46000?
IgorC [24]
I think it is the tens because the first is ten thousand, second is thousand, third is hundreds and last is units ones
4 0
3 years ago
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Help me plssss <br> its for a math test and im braindead atm
Gwar [14]

Answer:

5/8

Step-by-step explanation:

3/8 + 1/4

To add these fractions, you need a lowest common denominator.  Both 4 and 8 "go into" 8, so the lowest common denominator is 8.

In order to change the denominator 4 to 8, you need to multiply both the numerator and the denominator by 2.  So, 1/4 becomes 2/8.

Now, the problem is 3/8 + 2/8.  

You can add the numerators, because the denominator is the same for each fraction.

3/8 + 2/8 = 5/8

5 0
3 years ago
Read 2 more answers
I need help with this
N76 [4]

Answer:

The x-intercepts are x = 1 , x = 2 , x = 3

The y-intercept is -6

Step-by-step explanation:

* Lets explain how to solve the problem

- To find the x-intercept of a function substitute f(x) by 0

- To find the y-intercept of a function substitute x by 0

- To find the factors of quadratic function use the long division

* Lets solve the problem

∵ f(x) = x³ - 6x² + 11x - 6

∵ (x - 3) is one of its factors

- Use the long division to find the other factors

∵ x³ - 6x² + 11x - 6 ⇒ dividend

∵ x - 3 ⇒ divisor

# Divide the 1st term in the dividend by the 1st term of the divisor

∵ x³ ÷ x = x²

# Multiply x² by the divisor (x - 3)

∵ x²(x - 3) = x³ - 3x²

# subtract it from the dividend

∵ (x³ - 6x² + 11x - 6) - (x³ - 3x²) = (x³ - x³) + (-6x² + 3x²) +11x - 6

∴ The dividend is -3x² + 11x - 6

# Divide the 1st term in the dividend by the 1st term of the divisor

∵ -3x² ÷ x = -3x

# Multiply -3x by the divisor (x - 3)

∴ -3x(x - 3) = -3x² + 9x

# subtract it from the dividend

∵ (-3x² + 11x - 6) - (-3x² + 9x) = (-3x² - 3x²) + (11x - 9x) - 6

∴ The dividend is 2x - 6

# Divide the 1st term in the dividend by the 1st term of the divisor

∵ 2x ÷ x = 2

# Multiply 2 by the divisor (x - 3)

∴ 2(x - 3) = 2x - 6

# subtract it from the dividend

∴ (2x - 6) - (2x - 6) = (2x - 2x) + (-6 + 6) = 0

∴ (x³ - 6x² + 11x - 6) ÷ (x - 3) = x² - 3x + 2

∴ The factors of f(x) are (x - 3)( x² - 3x + 2)

- The factor (x² - 3x + 2) can factorize into two bracket

∵ The last term is positive and the middle term is negative than the

   two brackets have the middle sign (-)

∵ x × x = x² ⇒ 1st terms in the two brackets

∵ 2 × 1 = 2 ⇒ 2nd terms in the two brackets

∵ 2 × x = 2x

∵ 1 × x = x

∵ 2x + x = 3x

∴  (x² - 3x + 2) = (x - 2)(x - 1)

∴ f(x) = (x - 3)(x - 2)(x - 1)

- To find the x-intercept put f(x) = 0

∴ (x - 3)(x - 2)(x - 1) = 0

- That means each bracket = 0

∵ x - 3 = 0 ⇒ add 3 for both sides

∴ x = 3

∵ x - 2 = 0 ⇒ add 2 for both sides

∴ x = 2

∵ x - 1 = 0 ⇒ add 1 for both sides

∴ x = 1

∴ The x-intercepts are x = 1 , x = 2 , x = 3

- To find the y-intercept put x = 0

∵ f(x) = x³ - 6x² + 11x - 6

∵ x = 0

∴ f(0) = 0 - 0 + 0 - 6 = -6

∴ The y-intercept is -6

4 0
3 years ago
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