What we know:
Football field is 100 yards in length
End zones are 10 yards each in length
Perimeter between pylons is 306 2/3 yards
What we need to find:
a. Perimeter and area of one end zone
b. Perimeter and area of without end zones
c. Perimeter and area of playing field with end zones
First we need to find the measurements of the field between pylons using the perimeter of 306 2/3 yards. We already know the length is 100 yards so we need to find width (w).
P=2l + 2w
306 2/3=2 (100) + 2w
306 2/3= 200 + 2w
300 2/3-200=200-200+2w
106 2/3=2w
106 2/3/2=2/2w
53 1/3=w
a. Perimeter=2 (10)+2 (53 1/3)=126 2/3 yards
Area=10×53 1/3=533 1/3 yd²
b. Perimeter=2 (100)+2 (53 1/3)=306 2/3 yards
Area=100×53 1/3=5333 1/3 yd²
c. Perimeter=2 (120) + 2 (53 1/3)=346 2/3 yards
Area=120×53 1/3=6400 yd²
Answer:
Step-by-step explanation:
(Given)
Squares : Triangles
3 : 12
Divide both sides by 3.
The simplest ratio is
1 : 4
Answer:
market
Step-by-step explanation:
<u>Market</u>
1 dozen bagels = 12 bagels
⇒ Cost per bagel = $7.00 ÷ 12 = $0.58 (nearest cent)
<u>Bagel shop</u>
Cost per bagel = $0.60
As $0.58 < $0.60 the market is a better buy
Answer:
-16
Step-by-step explanation:
a/-2=8
you multiply -2 on both side a/-2(-2)=8(-2)
-2 cancels out one the one side
your final answer is a= -16
