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Grace [21]
3 years ago
11

A champion bicyclist training in a flat, open area rode 84 kilometers against the wind in 6hours. Riding with the wind, it took

her 1 hour to ride the same distance on the return trip. Find the rate of the bicyclist in calm air and the rate of the wind
Mathematics
1 answer:
Katena32 [7]3 years ago
8 0

84 \div 6 =  \times 1

so 6 ÷ 84=0.0714285714 then ×1 still =0.0714285714. so 0.0714285714 is the calm air and rate of the wind

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7 0
3 years ago
Read 2 more answers
(Geometry)
ArbitrLikvidat [17]

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mash [69]

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5 0
4 years ago
Read 2 more answers
Let f(x)=−14(x+4)2−8 .
nevsk [136]
Answer:
Average rate of change = -112

Explanation:
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where:
b is the upper limit = 2
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a is the lower limit = -2
f(a) = f(-2) = -14(-2+4)² - 8 = -64

Substitute with these values in the above equation to get the average rate of change as follows:
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Hope this helps :)
3 0
3 years ago
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8x-2(xx9)=x+47. solve for x
Dafna11 [192]
18x-8x2=0

Two solutions were found :

x = 9/4 = 2.250
x = 0
Step by step solution :

Step 1 :

Equation at the end of step 1 :

18x - 23x2 = 0
6 0
4 years ago
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