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ivanzaharov [21]
3 years ago
9

A ball is thrown straight up and reaches a maximum height of 5 m.

Physics
1 answer:
love history [14]3 years ago
5 0

Answer:

9.9 m/s

Explanation:

Given:

Δy = 5 m

v = 0 m/s

a = -9.8 m/s²

Find: v₀

v² = v₀² + 2aΔy

(0 m/s)² = v₀² + 2 (-9.8 m/s²) (5 m)

v₀ = 9.9 m/s

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A speaker generates a continuous tone of 440 Hz. In the drawing, sound travels into a tube that splits into two segments, one lo
chubhunter [2.5K]

Answer:

The minimum difference between the lengths of the two tubes should be 0.385 meters.

Explanation:

As we known that for any two waves to arrive in phase at any point the difference in the path traveled by the waves should be an integral multiple of the wavelength of the wave.

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\Delta x=n\frac{\lambda }{2}

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Applying values we get

\lambda =\frac{339}{440 }=0.77m

Thus the minimum difference in the lengths of the tubes can be obtained by putting the value of n = 1

\therefore \Delta x=1\times \frac{0.77}{2}=0.385m

7 0
4 years ago
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4 years ago
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