A(n) ________ has charge but negligible mass, whereas a(n) ________ has mass but no charge.
2 answers:
Answer:
An electron has charge but negligible mass, whereas a neutron has mass but no charge.
Explanation:
Atoms are made of equal number of protons and electrons. Almost all the mass of an atom is in the nucleus of the atom. The nucleus is made of protons and neutrons (except hydrogen, which has no neutron)
The charge of an electron is C
The charge of a proton is C
The charge of a neutron is 0 C
The mass of a proton is kg or 1.007276 u
The mass of a neutron is kg or 1.008664 u
The mass of an electron is kg or 0.00054858 u
As we can see the proton is 1,838 times heavier than an electron and the neutron is 1,840 times heavier than an electron.
So the electron has a negligible mass and a negative charge but the neutron has no charge but it is heavier than electron and proton
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The distance traveled by the hockey player is 0.025 m.
<h3>The principle of conservation of linear momentum;</h3>- The principle of conservation of linear momentum states that, the total momentum of an isolated system is always conserved.
The final velocity of the hockey play is calculated by applying the principle of conservation of linear momentum;
The time taken for the puck to reach 15 m is calculated as follows;
The distance traveled by the hockey player at the calculated time is;
Learn more about conservation of linear momentum here: brainly.com/question/7538238
Answer:
μsmín = 0.1
Explanation:
- There are three external forces acting on the riders, two in the vertical direction that oppose each other, the force due to gravity (which we call weight) and the friction force.
- This friction force has a maximum value, that can be written as follows:
where μs is the coefficient of static friction, and Fn is the normal force,
perpendicular to the wall and aiming to the center of rotation.
- This force is the only force acting in the horizontal direction, but, at the same time, is the force that keeps the riders rotating, which is the centripetal force.
- This force has the following general expression:
where ω is the angular velocity of the riders, and r the distance to the
center of rotation (the radius of the circle), and m the mass of the
riders.
Since Fc is actually Fn, we can replace the right side of (2) in (1), as
follows:
- When the riders are on the verge of sliding down, this force must be equal to the weight Fg, so we can write the following equation:
- (The coefficient of static friction is the minimum possible, due to any value less than it would cause the riders to slide down)
- Cancelling the masses on both sides of (4), we get:
- Prior to solve (5) we need to convert ω from rev/min to rad/sec, as follows:
- Replacing by the givens in (5), we can solve for μsmín, as follows: