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Nina [5.8K]
3 years ago
10

A(n) ________ has charge but negligible mass, whereas a(n) ________ has mass but no charge.

Physics
2 answers:
Dahasolnce [82]3 years ago
7 0

Answer:

An electron has charge but negligible mass, whereas a neutron has mass but no charge.

Explanation:

Atoms are made of equal number of protons and electrons. Almost all the mass of an atom is in the nucleus of the atom. The nucleus is made of protons and neutrons (except hydrogen, which has no neutron)

The charge of an electron is -1.6 \times 10^{-19} C

The charge of a proton is +1.6 \times 10^{-19} C

The charge of a neutron is 0 C

The mass of a proton is 1.6726 \times 10^{-27} kg or 1.007276 u

The mass of a neutron is 1.6749 \times 10^{-27} kg or 1.008664 u

The mass of an electron is 9.1 \times 10^{-31} kg or 0.00054858 u

As we can see the proton is 1,838 times heavier than an electron and the neutron is 1,840 times heavier than an electron.

So the electron has a negligible mass and a negative charge but the neutron has no charge but it is heavier than electron and proton

vfiekz [6]3 years ago
6 0
Electron;Neutron is the correct answer.
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A ball rolls forward in the grass slowing down as it rolls?
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A small sphere with mass m is attached to a massless rod of length L that is pivoted at the top, forming a simple pendulum. The
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Answer:

a) see attached, a = g sin θ

b)

c)   v = √(2gL (1-cos θ))

Explanation:

In the attached we can see the forces on the sphere, which are the attention of the bar that is perpendicular to the movement and the weight of the sphere that is vertical at all times. To solve this problem, a reference system is created with one axis parallel to the bar and the other perpendicular to the rod, the weight of decomposing in this reference system and the linear acceleration is given by

          Wₓ = m a

          W sin θ = m a

          a = g sin θ

b) The diagram is the same, the only thing that changes is the angle that is less

                θ' = 9/2  θ

             

c) At this point the weight and the force of the bar are in the same line of action, so that at linear acceleration it is zero, even when the pendulum has velocity v, so it follows its path.

The easiest way to find linear speed is to use conservation of energy

Highest point

            Em₀ = mg h = mg L (1-cos tea)

Lowest point

          Emf = K = ½ m v²

          Em₀ = Emf

          g L (1-cos θ) = v² / 2

              v = √(2gL (1-cos θ))

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