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dsp73
3 years ago
6

Which equation gives the value of the circumference, CC, of a circle with a diameter of 5656 feet?

Mathematics
1 answer:
Kaylis [27]3 years ago
7 0
The standard equation for circumference
CC= 2pi(D/2)
plug in variables
CC=2pi(5656/2)
so the equation would be
CC=(2)(pi)(2828)
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Simplify completely quantity 6 x minus 12 over 10.
Natali [406]
Hey! 
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so we are multiplying a positive number by a negative number. When you do that the answer will be a negative number. 
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3 years ago
How to simplify 4r + 4s + 3r + 3s + 5p
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Find (f −1)'(a).<br><br> f(x) = 4 + x2 + tan(πx/2), −1 &lt; x &lt; 1, a = 4
Vinvika [58]

Answer:

The  solution  is   (f^{-1})'(a) = \frac{2}{\pi }

Step-by-step explanation:

From the question we are told that

      The  function is  f(x) =  4 +  x^2  + tan [\frac{ \pi x}{2} ] ,     -1 <  x  <  1  a =  4

Here we are told find  (f^{-1}) (a)

Let equate

     f(x) =  a

So  

      4 +  x^2  + tan[\frac{\pi x }{2} ] =  4

       x^2  + tan[\frac{\pi x }{2} ]  =  0

For the equation above to be valid x must be equal to 0

  Now when x = 0

       f(0) = 4+0^2 + tan [\frac{ \pi * 0}{2} ]

=>      f(0) =  4

=>  0 =  f^{-1} (4)

Differentiating  f(x)

     f(x)'  =  0 + 2x  + sec^2 (\frac{\pi x}{2} )\cdot \frac{\pi}{2}

Now

    since 0 =  f^{-1} (4)

We have

      f(0)'  =  0 +  \frac{\pi }{2}  sec^2 (0)

       f(0)'  = \frac{\pi }{2}

Now  

        (f^{-1})'(a) =  \frac{1}{(\frac{\pi}{2} )}

        (f^{-1})'(a) = \frac{2}{\pi }

       

3 0
3 years ago
Help pls asap!!!!!!! brainliest!!!!!!
Rama09 [41]

Answer:

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Step-by-step explanation:

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Hunter-Best [27]

Answer:

6/5

Step-by-step explanation:

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