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natka813 [3]
3 years ago
9

How many times greater is the value of the digit 8 in 82.77 than the value of the digit 8 in 20.18

Mathematics
1 answer:
Kitty [74]3 years ago
3 0

Answer:

Option 3. 1,000 times

Step-by-step explanation:

we know that

The value of digit 8 in 82.77 is equal to 80

The value of digit 8 in 20.18 is 0.08

so

Divide 80 by 0.08

80/0.08=1,000 times

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Answer:

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2 years ago
Question B,C and D I need answers to these parts.
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Explanation<h2>Part b</h2>

So in part (b) we must give the annual growth factor. For any quantity that increases annualy, this factor is the number by which the quantity multiplies itself every year. For a given quantity that increases at a rate of p% its growth factor is given by:

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In this case the production of ethanol increases at a rate of 5.5% per year which means that the growth factor is:

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In part (c) we must write an equation that models the increase in the ethanol production. Given an initial qunatity Q and an annual growth factor k the quantity after x years is given by multiplying the initial quantity by the growth factor raised to the x. Then we get:

C(x)=Q\cdot k^x

In this case we need a function for the amount of ethanol produced E, x years after 1990. The 0.9 billion gallons produced that year compose our initial quantity and knowing that the annual growth factor is 1.055 we have the desire equation:

E(x)=0.9\cdot1.055^x

And that's the answer to part (c).

In part (d) we have to compare the actual production of ethanol in 2008 to the one predicted by the equation of part (c). Remember that x represents the years passed after 1990 so for the year 2008 the value of x is given by:

x=2008-1990=18

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