We are given a right triangle that has angles of 45°-45°-90°. This would
indicate that the triangle is an isosceles type. We can use some
trigonemetric functions to solve for the other legs. We do as follows:
sin 45 = p / 10
p = 5√2
cos 45 = q /10
q = 5√2
<span>Hope this answers the question. Have a nice day.</span>
t N.
In the figure shown below
Answer:
A horizontal line segment M K intersects with line segment J L at their midpoint N.
∠J N M =(5x+2)°
∠ LN M=3( x+ 14)°
So, ∠J N M + ∠ LN M =180°[ These two angles form linear pair.Angles forming linear pair are supplementary.]
⇒5 x+ 2+ 3 (x+ 14) =180 [ By Substitution]
⇒ 5 x+2 +3 x+42°= 180°
⇒ 8 x=180°-44°
⇒8 x= 136°
⇒x= 136°÷8
⇒x=17°
So, ∠J N M =5×17 +2=87°
∠ LN M= 3×(17 +14)=3×31=93
∠J N M =∠K N L [Vertically opposite angles]
∠K N L=87°
Answer:
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Answer:
3
Step-by-step explanation: