To prove that <span>AEC≅ AED, we need to write following proofs or statement reasons.
It is given that points C and D are equidistant to point A. Hence,
</span><span>AD ≅ AC
Next, </span><span>CAE ≅ DAE. AE is the common side or the included side.
</span><span>
Then, </span><span>AE ≅ EA by Reflexive Property of Congruence as it is congruent to itself.
Lastly, </span><span>EAD ≅ EAC by Symmetric Property of Congruence as these triangles are mirror image of each other.
</span>
Therefore, we can conclude that AEC≅ AED by SSS or Side-Side-Side. That is when all sides of triangles are congruent then both triangles are deemed to be equal.
Answer: b= - -log10(7)+3/2
Step-by-step explanation: log 10 (7) -2b-9=-6 : b= - -log10(7)+3/2 (Decimal : b = -1.07745...)
so these are the steps how I got it I did log 10 (7)-2b-9=-6 subtract log 10 (7) -9 from both sides log 10 (7)-2b-9-(log10(7)-9)=-6-(log 10 (7) -9)
Simplify -2b= -log10(7)+3
Divide both sides by -2 -2b/2= - log 10(7)/-2+ 3/-2 if you simplify it should give you b= - -log10(7)+3/2 that should be your answer but i'm not sure those I think that's how you do it let me know if you got it right bye!
Step-by-step explanation:
- (√3+√7)(√3+√7)
- (√3)^2+[(√3*√7)+(√3*√7)]+(√7)^2
- 3+2√21+7
- 10+2√21
Answer:
Only the x-value changes.
Step-by-step explanation:
When a point is reflected over the y-axis, it is the x-axis number that will flip it's sign.
When a point is reflected over the x-axis, it is the y-axis number that will flip it's sign.
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