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AysviL [449]
2 years ago
10

Jorge solves the equation 4 x minus (x + 2) + 6 = 2 (3 x + 8) using the steps below. Step 1: 4 x minus x + 2 + 6 = 6 x + 16 Step

2: 3 x + 8 = 6 x + 16 Step 3: 8 minus 16 = 6 x minus 3 x Step 4: Negative 8 = 3 x Step 5: Negative StartFraction 8 Over 3 EndFraction = x Jorge verifies his solution by substituting Negative StartFraction 8 Over 3 EndFraction into the original equation for x. He determines that his solution is incorrect. Which best describes Jorge’s error? Jorge distributed incorrectly. Jorge incorrectly combined like terms. Jorge incorrectly applied the addition and subtraction properties of equality. Jorge incorrectly applied the multiplication and division properties of equality.
Mathematics
2 answers:
mart [117]2 years ago
5 0
End fraction is a lot of math lol but try the 16=6 x
Vladimir79 [104]2 years ago
4 0

Answer:

Jorge incorrectly applied the multiplication and division properties of equality.

Step-by-step explanation:

D on edg

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Am i right?? please help!
ladessa [460]

Answer: yes

Step-by-step explanation:

5 0
3 years ago
Evaluate the integral. (sec2(t) i t(t2 1)8 j t7 ln(t) k) dt
polet [3.4K]

If you're just integrating a vector-valued function, you just integrate each component:

\displaystyle\int(\sec^2t\,\hat\imath+t(t^2-1)^8\,\hat\jmath+t^7\ln t\,\hat k)\,\mathrm dt

=\displaystyle\left(\int\sec^2t\,\mathrm dt\right)\hat\imath+\left(\int t(t^2-1)^8\,\mathrm dt\right)\hat\jmath+\left(\int t^7\ln t\,\mathrm dt\right)\hat k

The first integral is trivial since (\tan t)'=\sec^2t.

The second can be done by substituting u=t^2-1:

u=t^2-1\implies\mathrm du=2t\,\mathrm dt\implies\displaystyle\frac12\int u^8\,\mathrm du=\frac1{18}(t^2-1)^9+C

The third can be found by integrating by parts:

u=\ln t\implies\mathrm du=\dfrac{\mathrm dt}t

\mathrm dv=t^7\,\mathrm dt\implies v=\dfrac18t^8

\displaystyle\int t^7\ln t\,\mathrm dt=\frac18t^8\ln t-\frac18\int t^7\,\mathrm dt=\frac18t^8\ln t-\frac1{64}t^8+C

8 0
3 years ago
Mason, a hardwood flooring installer, needs to calculate the amount of hardwood flooring needed to cover a floor that's 33⁄4 yar
Aleksandr-060686 [28]

Answer:

20 5/8 yd^2

Step-by-step explanation:

width = 3 3/4 yd

length = 5 1/2 yd

First change both measurements to fractions.

3 3/4 = 3 + 3/4 = 12/4 + 3/4 = 15/4

5 1/2 = 5 + 1/2 = 10/2 + 1/2 = 11/2

area = length * width

area = 15/4 yd * 11/2 yd

area = (15 * 11)/(4 * 2) yd^2

area = 165/8 yd^2

165/8 = 20 remainder 5

area = 20 5/8 yd^2

3 0
3 years ago
The answer and how to solve the problem
SVETLANKA909090 [29]
A
I hope you get it right, you have a god day!!!

7 0
3 years ago
If the outliers are not included, what is the mean of the data set? 76, 79, 80, 82, 50, 78, 83, 79, 81, 82 (2 points) Select one
wlad13 [49]
Hello!

As you can see, 50 is the outlier, as it is not around the other numbers in the data set. Therefore, we will calculate the mean of all the numbers if we add up all the numbers and divide by 9.

(76+79+80+82+78+83+79+81+82)÷9=80

The mean of this data set (excluding the outlier) is 80.

I hope this helps!
6 0
3 years ago
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