The two fractions that added together give you a sum of -7/24 are 1/24+-8/24= -7/24
You can first multiply your coefficients (7x9), which gives you 63. You can then simplify the exponents by using the rule that when two terms with the same variable are being multiplied, you can simplify by adding exponents. Since 7+3= 10, your simplified answer would be 63x^10 :) hope it helped!
Answer:
b+6
Problem:
If the average of b and c is 8, and d=3b-4, what is the average of c and d in terms of b?
Step-by-step explanation:
We are given (b+c)/2=8 and d=3b-4.
We are asked to find (c+d)/2 in terms of variable, b.
We need to first solve (b+c)/2=8 for c.
Multiply both sides by 2: b+c=16.
Subtract b on both sides: c=16-b
Now let's plug in c=16-b and d=3b-4 into (c+d)/2:
([16-b]+[3b-4])/2
Combine like terms:
(12+2b)/2
Divide top and bottom by 2:
(6+1b)/1
Multiplicative identity property applied:
(6+b)/1
Anything divided by 1 is that anything:
(6+b)
6+b
b+6
Answer:
y = -3x + 1
Step-by-step explanation:
slope = -3
y = mx + b
7 = -3(-2) + b
7 = 6 + b
1 = b
y = -3x + 1
32 gallons of 25 % antifreeze should be combined with 8 gallons of 50 % antifreeze to get 40 gallon of 30% antifreeze
<h3><u>
Solution:</u></h3>
From given,
Final mixture is 40 gallon
Let "x" be the gallon of 25 % antifreeze
Then, (40 - x) is the gallon of 50 % antifreeze
Therefore, according to question,
"x" gallons of 25 % antifreeze should be combined with (40 - x) gallons of 50 % antifreeze to get 40 gallon of 30% antifreeze
<h3><u>Therefore, we frame a equation as:</u></h3>
25 % of x + 50 % of (40 - x) = 30 % of 40
Solve for "x"
Thus, 32 gallons of 25 % antifreeze is used
Then, (40 - x) = (40 - 32) = 8
Thus 8 gallons of 50 % antifreeze is used
