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musickatia [10]
3 years ago
10

FACTORIZAR LOS SIGUIENTES POLINOMIOS. a2 - 81 =

Mathematics
1 answer:
Molodets [167]3 years ago
5 0
I’m not sure but 3.5
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Which of the following geometric objects could have it length measured
anastassius [24]

Answer:

You need to attach the image

Step-by-step explanation:

3 0
3 years ago
A pecan pie is being served for dessert. One piece of pie has an arc length of 7.85 in. It has been cut into 8 equal pieces. Wha
grin007 [14]

Answer:

The radius of the pie is 6.17 in.

Step-by-step explanation:

The formula for arc length as a function of radius is

s = r·Ф, where Ф is the central angle in radians.

Here we know that the arc length is 7.85 in.  Assuming that the whole pie has been cut into 8 equal pieces, the central angle of one such piece is

2π / 8, or π /4 (radians).

thus, s = r·Ф, solved for r, is r = s/Ф

and in this instance r = (7.85 in)/(π/4).  Evaluating this, we get:

                                 r = 6.17 in

The radius of the pie is 6.17 in.

8 0
4 years ago
In 687,332,195, how is the value of the three in the ten thousands place related to the value of the 3 in the hundred thousands
olganol [36]
<span>In this case, the value of the first 3 (the ten-thousands) has a value of 30,000. The 3 next to it, in the hundred-thousands place, has a value of 300,000. To compare the two, the 3 on the right has a value one-tenth as much as that on the left.</span>
8 0
4 years ago
Read 2 more answers
What is the radius of a circle in it in if the area is 36m²?
allsm [11]

Answer:

B. 3.39 m

Step-by-step explanation:

r² = A/π

= 36/3.14

= 11.465

r = √11.465 = 3.39

4 0
3 years ago
A restaurant sells about 330 sandwiches each day at a price of $6 each $.25 decrease in price. 15 more sandwiches are sold per d
zmey [24]

Answer:

restaurant should charge $(6-0.25) = $5.75per sandwich to maximize daily revenue.

the revenue is $1983.75

Step-by-step explanation:

to calculate current revenue= $6 x 330 = $1980

suppose x as the number of times the price to be dropped by $0.25

then find new price.. i.e

new price= $(6-0.25x)

and, new sell=330 +15x sandwiches

therefore, the new revenue would be= (6-0.25x)(330 +15x)

in order to maximize the current revenue, simplify the above equation and make it complete square using x

(6-0.25x)(330 +15x)

=1980-82.5x +90x -3.75x^{2}

=1980 + 7.5x -3.75x^{2}

=1980-3.75 (-2x+x^{2}) ----> taking out common

now, to make a complete square lets add and subtract 1 inside the parentheses

=1980-3.75(-1+1-2x+x^{2})

=1980 +3.75 -3.75(x^{2} -2x +1)

=1983.75 -3.75 (x-1)^{2}---->(1)

as (x-1)^{2} is positive always, minimize the other term in order to maximize the total revenue.

so the minimum possible value of (x-1)^{2} = 0

therefore, x=1

putting x in eq(1) the revenure becomes,

$(1983.75-0)=> $1983.75

therefore, restaurant should charge $(6-0.25) = $5.75per sandwich to maximize daily revenue.

the revenue is $1983.75

3 0
3 years ago
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